What are the solutions to the equation 6x^2-7x-2=0 ?

The solutions to the equation 6x^2-7x-2=0 are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)

Find the zeros of 6x^2-7x-2=0

The zeros of 6x^2-7x-2=0 are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)

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6 x^{2} - 7 x - 2 = 0

x = \frac{7 + 97}{12}, x = \frac{7 - 97}{12}

Decimal Notation

x = 1.40407 \dots, x = - 0.23740 \dots

Solution steps

6 x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 (- 2) = 97

x_{1, 2} = \frac{- ( - 7 ) \pm 97}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 97}{2 \cdot 6}, x_{2} = \frac{- ( - 7 ) - 97}{2 \cdot 6}

x = \frac{- ( - 7 ) + 97}{2 \cdot 6} : \frac{7 + 97}{12}

x = \frac{- ( - 7 ) - 97}{2 \cdot 6} : \frac{7 - 97}{12}

The solutions to the quadratic equation are:

x = \frac{7 + 97}{12}, x = \frac{7 - 97}{12}

1 + 14 x^{2} y + 49 x^{4} y^{2}

48 = 10 w - 7 w

- \frac{1.95 E 26}{π ( 1.5 \cdot 1 0 ^{11} ) ^{3}}

\frac{m - 3}{2} \leq 5

x^{3} - x^{2} + 6 x - 6

What are the solutions to the equation 6x^2-7x-2=0 ?
The solutions to the equation 6x^2-7x-2=0 are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)
Find the zeros of 6x^2-7x-2=0
The zeros of 6x^2-7x-2=0 are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)