What are the solutions to the equation 4x^2-80x+360=0 ?

The solutions to the equation 4x^2-80x+360=0 are x=10+sqrt(10),x=10-sqrt(10)

Find the zeros of 4x^2-80x+360=0

The zeros of 4x^2-80x+360=0 are x=10+sqrt(10),x=10-sqrt(10)

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4 x^{2} - 80 x + 360 = 0

x = 10 + 10, x = 10 - 10

Decimal Notation

x = 13.16227 \dots, x = 6.83772 \dots

Solution steps

4 x^{2} - 80 x + 360 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 4 \cdot 360}{2 \cdot 4}

(- 80)^{2} - 4 \cdot 4 \cdot 360 = 810

x_{1, 2} = \frac{- ( - 80 ) \pm 8 10}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 80 ) + 8 10}{2 \cdot 4}, x_{2} = \frac{- ( - 80 ) - 8 10}{2 \cdot 4}

x = \frac{- ( - 80 ) + 8 10}{2 \cdot 4} : 10 + 10

x = \frac{- ( - 80 ) - 8 10}{2 \cdot 4} : 10 - 10

The solutions to the quadratic equation are:

x = 10 + 10, x = 10 - 10

\frac{3}{80} x^{2}

\frac{n}{3} - 8 = - 2

4 s^{2} + 16 s + 25 = 0

- 2 x^{2} + 12 x = 0

45 x^{2} - 9 x - 9

What are the solutions to the equation 4x^2-80x+360=0 ?
The solutions to the equation 4x^2-80x+360=0 are x=10+sqrt(10),x=10-sqrt(10)
Find the zeros of 4x^2-80x+360=0
The zeros of 4x^2-80x+360=0 are x=10+sqrt(10),x=10-sqrt(10)