What are the solutions to the equation 2(x-9)^2-43=-9 ?

The solutions to the equation 2(x-9)^2-43=-9 are x=sqrt(17)+9,x=-sqrt(17)+9

Find the zeros of 2(x-9)^2-43=-9

The zeros of 2(x-9)^2-43=-9 are x=sqrt(17)+9,x=-sqrt(17)+9

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2 (x - 9)^{2} - 43 = - 9

x = 17 + 9, x = - 17 + 9

Decimal Notation

x = 13.12310 \dots, x = 4.87689 \dots

Solution steps

2 (x - 9)^{2} - 43 = - 9

Move

43

to the right side

2 (x - 9)^{2} = 34

Divide both sides by

2

(x - 9)^{2} = 17

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 9 = 17 : x = 17 + 9

Solve

x - 9 = - 17 : x = - 17 + 9

The solutions to the quadratic equation are:

x = 17 + 9, x = - 17 + 9

27 a^{3} - 8 b^{3}

\frac{4 x}{3 - x} \geq 4 x

x^{2} + 6 x > 27

27 p^{3} + 125 z^{3}

- 2 (y + 6) + 6 y = 4 (y - 3)

What are the solutions to the equation 2(x-9)^2-43=-9 ?
The solutions to the equation 2(x-9)^2-43=-9 are x=sqrt(17)+9,x=-sqrt(17)+9
Find the zeros of 2(x-9)^2-43=-9
The zeros of 2(x-9)^2-43=-9 are x=sqrt(17)+9,x=-sqrt(17)+9