What are the solutions to the equation x^2+10x+25=8 ?

The solutions to the equation x^2+10x+25=8 are x=-5+2sqrt(2),x=-5-2sqrt(2)

Find the zeros of x^2+10x+25=8

The zeros of x^2+10x+25=8 are x=-5+2sqrt(2),x=-5-2sqrt(2)

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x^{2} + 10 x + 25 = 8

x = - 5 + 22, x = - 5 - 22

Decimal Notation

x = - 2.17157 \dots, x = - 7.82842 \dots

Solution steps

x^{2} + 10 x + 25 = 8

Move

8

to the left side

x^{2} + 10 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 17 = 42

x_{1, 2} = \frac{- 10 \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 4 2}{2 \cdot 1}, x_{2} = \frac{- 10 - 4 2}{2 \cdot 1}

x = \frac{- 10 + 4 2}{2 \cdot 1} : - 5 + 22

x = \frac{- 10 - 4 2}{2 \cdot 1} : - 5 - 22

The solutions to the quadratic equation are:

x = - 5 + 22, x = - 5 - 22

- 2 x > 20

- 2 y + 5 \leq 9

\frac{1}{2 - x} \geq x + 2

9 x^{3} - 36 x^{2} - 25 x + 100

5 x^{2} + 30 x = 125

What are the solutions to the equation x^2+10x+25=8 ?
The solutions to the equation x^2+10x+25=8 are x=-5+2sqrt(2),x=-5-2sqrt(2)
Find the zeros of x^2+10x+25=8
The zeros of x^2+10x+25=8 are x=-5+2sqrt(2),x=-5-2sqrt(2)