What are the solutions to the equation b^2+9b-14=6b ?

The solutions to the equation b^2+9b-14=6b are b=(-3+sqrt(65))/2 ,b=(-3-sqrt(65))/2

Find the zeros of b^2+9b-14=6b

The zeros of b^2+9b-14=6b are b=(-3+sqrt(65))/2 ,b=(-3-sqrt(65))/2

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b^{2} + 9 b - 14 = 6 b

b = \frac{- 3 + 65}{2}, b = \frac{- 3 - 65}{2}

Decimal Notation

b = 2.53112 \dots, b = - 5.53112 \dots

Solution steps

b^{2} + 9 b - 14 = 6 b

Move

6 b

to the left side

b^{2} + 3 b - 14 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 14) = 65

b_{1, 2} = \frac{- 3 \pm 65}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- 3 + 65}{2 \cdot 1}, b_{2} = \frac{- 3 - 65}{2 \cdot 1}

b = \frac{- 3 + 65}{2 \cdot 1} : \frac{- 3 + 65}{2}

b = \frac{- 3 - 65}{2 \cdot 1} : \frac{- 3 - 65}{2}

The solutions to the quadratic equation are:

b = \frac{- 3 + 65}{2}, b = \frac{- 3 - 65}{2}

x^{2} - x + 3 = 2 x^{2} - 5 x - 29

12 m n^{2} + 6 m^{2} n + 2 m

- 4 x + 60 < 72

2 a^{2} - 9 a - 5

x^{2} - 10 x - 24

What are the solutions to the equation b^2+9b-14=6b ?
The solutions to the equation b^2+9b-14=6b are b=(-3+sqrt(65))/2 ,b=(-3-sqrt(65))/2
Find the zeros of b^2+9b-14=6b
The zeros of b^2+9b-14=6b are b=(-3+sqrt(65))/2 ,b=(-3-sqrt(65))/2