What are the solutions to the equation -6x^2+36x-48=0 ?

The solutions to the equation -6x^2+36x-48=0 are x=2,x=4

Find the zeros of -6x^2+36x-48=0

The zeros of -6x^2+36x-48=0 are x=2,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 6 x^{2} + 36 x - 48 = 0

x = 2, x = 4

Solution steps

- 6 x^{2} + 36 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 ( - 6 ) ( - 48 )}{2 ( - 6 )}

3 6^{2} - 4 (- 6) (- 48) = 12

x_{1, 2} = \frac{- 36 \pm 12}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 36 + 12}{2 ( - 6 )}, x_{2} = \frac{- 36 - 12}{2 ( - 6 )}

x = \frac{- 36 + 12}{2 ( - 6 )} : 2

x = \frac{- 36 - 12}{2 ( - 6 )} : 4

The solutions to the quadratic equation are:

x = 2, x = 4

t^{3} \cdot t^{4} \cdot t^{2}

- 3 x^{2} - x - 3 = 0

4 (- \frac{1}{2})

\frac{1}{6} - \frac{1}{8}

26 r^{3} s + 52 r^{5} - 39 r^{2} s^{4}

What are the solutions to the equation -6x^2+36x-48=0 ?
The solutions to the equation -6x^2+36x-48=0 are x=2,x=4
Find the zeros of -6x^2+36x-48=0
The zeros of -6x^2+36x-48=0 are x=2,x=4