What is -(x+1)(x+2)(x+3)<0 ?

The solution to -(x+1)(x+2)(x+3) -1

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-(x+1)(x+2)(x+3)<0

- (x + 1) (x + 2) (x + 3) < 0

- 3 < x < - 2 or x > - 1

Interval Notation

(- 3, - 2) \cup (- 1, \infty)

Solution steps

- (x + 1) (x + 2) (x + 3) < 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x + 1) (x + 2) (x + 3)) (- 1) > 0 \cdot (- 1)

Simplify

(x + 1) (x + 2) (x + 3) > 0

Identify the intervals

- 3 < x < - 2 or x > - 1

e^{- 0.2}

2 (x - 4) = 6 x

6 (y + 3) = 30

\frac{( 1 + i ) ( 1 - 2 i )}{3 + i}

\frac{x - 1}{2} - 2 \leq \frac{3 x - 2}{5}

What is -(x+1)(x+2)(x+3)<0 ?
The solution to -(x+1)(x+2)(x+3)<0 is -3<x<-2\lor x>-1