What is factor 5z^2+39z+28 ?

The solution to factor 5z^2+39z+28 is (5z+4)(z+7)

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factor 5z^2+39z+28

factor

5 z^{2} + 39 z + 28

(5 z + 4) (z + 7)

Solution steps

5 z^{2} + 39 z + 28

Break the expression into groups

= (5 z^{2} + 4 z) + (35 z + 28)

Factor out

z

from

5 z^{2} + 4 z : z (5 z + 4)

Factor out

7

from

35 z + 28 : 7 (5 z + 4)

= z (5 z + 4) + 7 (5 z + 4)

Factor out common term

5 z + 4

= (5 z + 4) (z + 7)

- 3 (2 x + 1) > - 2 (x + 6)

lo g_{3} (9)

\frac{5 ^{5}}{5 ^{2}}

1 - ∣ 4 q + 2 ∣ > - 9

4 x = 2 x + 4