What are the solutions to the equation -4x^2+56x+0=0 ?

The solutions to the equation -4x^2+56x+0=0 are x=0,x=14

Find the zeros of -4x^2+56x+0=0

The zeros of -4x^2+56x+0=0 are x=0,x=14

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- 4 x^{2} + 56 x + 0 = 0

x = 0, x = 14

Solution steps

- 4 x^{2} + 56 x + 0 = 0

Refine

- 4 x^{2} + 56 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

5 6^{2} - 4 (- 4) \cdot 0 = 56

x_{1, 2} = \frac{- 56 \pm 56}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 56 + 56}{2 ( - 4 )}, x_{2} = \frac{- 56 - 56}{2 ( - 4 )}

x = \frac{- 56 + 56}{2 ( - 4 )} : 0

x = \frac{- 56 - 56}{2 ( - 4 )} : 14

The solutions to the quadratic equation are:

x = 0, x = 14

\frac{- 1 - 2 i}{- 1 + 2 i}

(1 + \frac{0.06}{4})^{4}

\frac{1}{2 + 3}

200 x - x^{2} = 5 x + 6200

6 x^{2} y^{5} + 15 x y^{7}

What are the solutions to the equation -4x^2+56x+0=0 ?
The solutions to the equation -4x^2+56x+0=0 are x=0,x=14
Find the zeros of -4x^2+56x+0=0
The zeros of -4x^2+56x+0=0 are x=0,x=14