What are the solutions to the equation 8x^2+5x=-4 ?

The solutions to the equation 8x^2+5x=-4 are x=-5/16+i(sqrt(103))/(16),x=-5/16-i(sqrt(103))/(16)

Find the zeros of 8x^2+5x=-4

The zeros of 8x^2+5x=-4 are x=-5/16+i(sqrt(103))/(16),x=-5/16-i(sqrt(103))/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} + 5 x = - 4

x = - \frac{5}{16} + i \frac{103}{16}, x = - \frac{5}{16} - i \frac{103}{16}

Solution steps

8 x^{2} + 5 x = - 4

Move

4

to the left side

8 x^{2} + 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 8 \cdot 4}{2 \cdot 8}

Simplify

5^{2} - 4 \cdot 8 \cdot 4 : 103 i

x_{1, 2} = \frac{- 5 \pm 103 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 5 + 103 i}{2 \cdot 8}, x_{2} = \frac{- 5 - 103 i}{2 \cdot 8}

x = \frac{- 5 + 103 i}{2 \cdot 8} : - \frac{5}{16} + i \frac{103}{16}

x = \frac{- 5 - 103 i}{2 \cdot 8} : - \frac{5}{16} - i \frac{103}{16}

The solutions to the quadratic equation are:

x = - \frac{5}{16} + i \frac{103}{16}, x = - \frac{5}{16} - i \frac{103}{16}

2 x + 5 + 2 x + 3 x = 9 x + 7

\frac{- 3 ( x + 3 )}{2} < 6

12 x y^{\frac{1}{2}} - 3 x^{\frac{1}{2}} y

\frac{x}{- 5} \leq - 7

2 x^{2} - 4 x

What are the solutions to the equation 8x^2+5x=-4 ?
The solutions to the equation 8x^2+5x=-4 are x=-5/16+i(sqrt(103))/(16),x=-5/16-i(sqrt(103))/(16)
Find the zeros of 8x^2+5x=-4
The zeros of 8x^2+5x=-4 are x=-5/16+i(sqrt(103))/(16),x=-5/16-i(sqrt(103))/(16)