What are the solutions to the equation 6x^2+3x+2=0 ?

The solutions to the equation 6x^2+3x+2=0 are x=-1/4+i(sqrt(39))/(12),x=-1/4-i(sqrt(39))/(12)

Find the zeros of 6x^2+3x+2=0

The zeros of 6x^2+3x+2=0 are x=-1/4+i(sqrt(39))/(12),x=-1/4-i(sqrt(39))/(12)

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6 x^{2} + 3 x + 2 = 0

x = - \frac{1}{4} + i \frac{39}{12}, x = - \frac{1}{4} - i \frac{39}{12}

Solution steps

6 x^{2} + 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

Simplify

3^{2} - 4 \cdot 6 \cdot 2 : 39 i

x_{1, 2} = \frac{- 3 \pm 39 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 3 + 39 i}{2 \cdot 6}, x_{2} = \frac{- 3 - 39 i}{2 \cdot 6}

x = \frac{- 3 + 39 i}{2 \cdot 6} : - \frac{1}{4} + i \frac{39}{12}

x = \frac{- 3 - 39 i}{2 \cdot 6} : - \frac{1}{4} - i \frac{39}{12}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{39}{12}, x = - \frac{1}{4} - i \frac{39}{12}

p^{2} - 13 = 0

\frac{a ^{2} - 81}{a ^{2} - 9 a} \leq 0

0. 5^{10}

\frac{1}{2} - \frac{4}{9}

- 20 x^{2} y^{3} z + 32 y^{2} z^{2}

What are the solutions to the equation 6x^2+3x+2=0 ?
The solutions to the equation 6x^2+3x+2=0 are x=-1/4+i(sqrt(39))/(12),x=-1/4-i(sqrt(39))/(12)
Find the zeros of 6x^2+3x+2=0
The zeros of 6x^2+3x+2=0 are x=-1/4+i(sqrt(39))/(12),x=-1/4-i(sqrt(39))/(12)