What is (m^2-2m+1)/(2m^2-m-1) ?

The solution to (m^2-2m+1)/(2m^2-m-1) is (m-1)/(2m+1)

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simplify (m^2-2m+1)/(2m^2-m-1)

simplify

\frac{m ^{2} - 2 m + 1}{2 m ^{2} - m - 1}

\frac{m - 1}{2 m + 1}

Solution steps

\frac{m ^{2} - 2 m + 1}{2 m ^{2} - m - 1}

Factor

m^{2} - 2 m + 1 : (m - 1)^{2}

= \frac{( m - 1 ) ^{2}}{2 m ^{2} - m - 1}

Factor

2 m^{2} - m - 1 : (2 m + 1) (m - 1)

= \frac{( m - 1 ) ^{2}}{( 2 m + 1 ) ( m - 1 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(m - 1)^{2} = (m - 1) (m - 1)

= \frac{( m - 1 ) ( m - 1 )}{( 2 m + 1 ) ( m - 1 )}

Cancel the common factor:

m - 1

= \frac{m - 1}{2 m + 1}

\frac{12 x ^{5} y ^{3}}{4 x ^{- 1}}

\frac{15 b ^{10}}{( 5 b ^{5} ) ^{2}}

x - 4 \leq 2 and 3 x + 1 > - 8

6 x^{2} + 40 x = 14

15 - 5 k \geq 0

What is (m^2-2m+1)/(2m^2-m-1) ?
The solution to (m^2-2m+1)/(2m^2-m-1) is (m-1)/(2m+1)