What are the solutions to the equation x^2-2x=3 ?

The solutions to the equation x^2-2x=3 are x=3,x=-1

Find the zeros of x^2-2x=3

The zeros of x^2-2x=3 are x=3,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 2 x = 3

x = 3, x = - 1

Solution steps

x^{2} - 2 x = 3

Move

3

to the left side

x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

x = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

lo g_{\frac{1}{2}} (3)

2 - 5 c > 67

9 (5 - 4 x)^{2} - 43 = - 39

5 t (6 t + 4)^{\frac{- 1}{2}} + 6 (6 t + 4)^{\frac{1}{2}}

\frac{- 6}{- 3}

What are the solutions to the equation x^2-2x=3 ?
The solutions to the equation x^2-2x=3 are x=3,x=-1
Find the zeros of x^2-2x=3
The zeros of x^2-2x=3 are x=3,x=-1