What are the solutions to the equation x^2+11x+7=0 ?

The solutions to the equation x^2+11x+7=0 are x=(-11+sqrt(93))/2 ,x=(-11-sqrt(93))/2

Find the zeros of x^2+11x+7=0

The zeros of x^2+11x+7=0 are x=(-11+sqrt(93))/2 ,x=(-11-sqrt(93))/2

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x^{2} + 11 x + 7 = 0

x = \frac{- 11 + 93}{2}, x = \frac{- 11 - 93}{2}

Decimal Notation

x = - 0.67817 \dots, x = - 10.32182 \dots

Solution steps

x^{2} + 11 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 7 = 93

x_{1, 2} = \frac{- 11 \pm 93}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 93}{2 \cdot 1}, x_{2} = \frac{- 11 - 93}{2 \cdot 1}

x = \frac{- 11 + 93}{2 \cdot 1} : \frac{- 11 + 93}{2}

x = \frac{- 11 - 93}{2 \cdot 1} : \frac{- 11 - 93}{2}

The solutions to the quadratic equation are:

x = \frac{- 11 + 93}{2}, x = \frac{- 11 - 93}{2}

(3)^{3}

- 7 (- 3 y + 8) - 6 y = 4

150 s^{4} + 230 s^{3} + 397.9 s^{2} + 134.184 s

\frac{1620 ln ( 0.3 )}{ln ( 0.5 )}

0 = - 16 t^{2} + 160 t + 0

What are the solutions to the equation x^2+11x+7=0 ?
The solutions to the equation x^2+11x+7=0 are x=(-11+sqrt(93))/2 ,x=(-11-sqrt(93))/2
Find the zeros of x^2+11x+7=0
The zeros of x^2+11x+7=0 are x=(-11+sqrt(93))/2 ,x=(-11-sqrt(93))/2