What is (x^2(5+x)(x+6))/((x+7)(x-3))>= 0 ?

The solution to (x^2(5+x)(x+6))/((x+7)(x-3))>= 0 is x 3

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(x^2(5+x)(x+6))/((x+7)(x-3))>= 0

\frac{x ^{2} ( 5 + x ) ( x + 6 )}{( x + 7 ) ( x - 3 )} \geq 0

x < - 7 or - 6 \leq x \leq - 5 or x = 0 or x > 3

Interval Notation

(- \infty, - 7) \cup [- 6, - 5] \cup x = 0 \cup (3, \infty)

Solution steps

\frac{x ^{2} ( 5 + x ) ( x + 6 )}{( x + 7 ) ( x - 3 )} \geq 0

Identify the intervals

x < - 7 or - 6 \leq x \leq - 5 or x = 0 or x > 3

\frac{3 x}{2} + x = \frac{1}{3}

(x - 4)^{2} = 25

x^{2} + 22 = - 12 x

r^{2} - 5 r + 4 = 0

7 x^{2} - 3 x - 972 = 0

What is (x^2(5+x)(x+6))/((x+7)(x-3))>= 0 ?
The solution to (x^2(5+x)(x+6))/((x+7)(x-3))>= 0 is x<-7\lor-6<= x<=-5\lor x=0\lor x>3