2m^2+2m-12=0

解

2 m^{2} + 2 m - 12 = 0

m = 2, m = - 3

解答ステップ

2 m^{2} + 2 m - 12 = 0

解くとthe二次式

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 12) = 10

m_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 2}

解を分離する

m_{1} = \frac{- 2 + 10}{2 \cdot 2}, m_{2} = \frac{- 2 - 10}{2 \cdot 2}

m = \frac{- 2 + 10}{2 \cdot 2} : 2

m = \frac{- 2 - 10}{2 \cdot 2} : - 3

二次equationの解:

m = 2, m = - 3