What are the solutions to the equation y^2-4y=0 ?

The solutions to the equation y^2-4y=0 are y=4,y=0

Find the zeros of y^2-4y=0

The zeros of y^2-4y=0 are y=4,y=0

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y^{2} - 4 y = 0

y = 4, y = 0

Solution steps

y^{2} - 4 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

y_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, y_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

y = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

y = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 4, y = 0

\frac{1000 0 ^{2} \cdot 1.5 \cdot 1 0 ^{- 12}}{2.8}

2 (2 x + 3) = 2 x

\frac{x - 3}{5} \leq - 1

4 (y + 1) + y = 3 (y - 2) + 2

2 m^{3} + 2 m^{2} - 4 m

What are the solutions to the equation y^2-4y=0 ?
The solutions to the equation y^2-4y=0 are y=4,y=0
Find the zeros of y^2-4y=0
The zeros of y^2-4y=0 are y=4,y=0