What are the solutions to the equation 12x^2+12x-826=0 ?

The solutions to the equation 12x^2+12x-826=0 are x=(-3+sqrt(2487))/6 ,x=-(3+sqrt(2487))/6

Find the zeros of 12x^2+12x-826=0

The zeros of 12x^2+12x-826=0 are x=(-3+sqrt(2487))/6 ,x=-(3+sqrt(2487))/6

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12 x^{2} + 12 x - 826 = 0

x = \frac{- 3 + 2487}{6}, x = - \frac{3 + 2487}{6}

Decimal Notation

x = 7.81163 \dots, x = - 8.81163 \dots

Solution steps

12 x^{2} + 12 x - 826 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 12 ( - 826 )}{2 \cdot 12}

1 2^{2} - 4 \cdot 12 (- 826) = 42487

x_{1, 2} = \frac{- 12 \pm 4 2487}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 12 + 4 2487}{2 \cdot 12}, x_{2} = \frac{- 12 - 4 2487}{2 \cdot 12}

x = \frac{- 12 + 4 2487}{2 \cdot 12} : \frac{- 3 + 2487}{6}

x = \frac{- 12 - 4 2487}{2 \cdot 12} : - \frac{3 + 2487}{6}

The solutions to the quadratic equation are:

x = \frac{- 3 + 2487}{6}, x = - \frac{3 + 2487}{6}

2 u^{2} - 5 u - 7

\frac{2}{2 - 1}

9 e - 7 = 7 e - 11

8 (x + 1) + 1 < 3 (2 x) + 1

6 am - 3 m - 2 a + 1

What are the solutions to the equation 12x^2+12x-826=0 ?
The solutions to the equation 12x^2+12x-826=0 are x=(-3+sqrt(2487))/6 ,x=-(3+sqrt(2487))/6
Find the zeros of 12x^2+12x-826=0
The zeros of 12x^2+12x-826=0 are x=(-3+sqrt(2487))/6 ,x=-(3+sqrt(2487))/6