What are the solutions to the equation 8x^2+10x-3=0 ?

The solutions to the equation 8x^2+10x-3=0 are x= 1/4 ,x=-3/2

Find the zeros of 8x^2+10x-3=0

The zeros of 8x^2+10x-3=0 are x= 1/4 ,x=-3/2

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8 x^{2} + 10 x - 3 = 0

x = \frac{1}{4}, x = - \frac{3}{2}

Decimal Notation

x = 0.25, x = - 1.5

Solution steps

8 x^{2} + 10 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

1 0^{2} - 4 \cdot 8 (- 3) = 14

x_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 10 + 14}{2 \cdot 8}, x_{2} = \frac{- 10 - 14}{2 \cdot 8}

x = \frac{- 10 + 14}{2 \cdot 8} : \frac{1}{4}

x = \frac{- 10 - 14}{2 \cdot 8} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{3}{2}

(x - 4)^{2} = 16

z^{2} + 2 z - 35 = 0

\frac{r + 2}{8} = \frac{3}{2}

15 x^{2} + 31 x + 2

\frac{5.00 1 ^{2} - 5 ( 5.001 )}{5.00 1 ^{2} - 25}

What are the solutions to the equation 8x^2+10x-3=0 ?
The solutions to the equation 8x^2+10x-3=0 are x= 1/4 ,x=-3/2
Find the zeros of 8x^2+10x-3=0
The zeros of 8x^2+10x-3=0 are x= 1/4 ,x=-3/2