|8-2x|>2

Lösung

∣ 8 - 2 x ∣ > 2

x < 3 or x > 5

Intervall-Notation

(- \infty, 3) \cup (5, \infty)

Schritte zur Lösung

∣ 8 - 2 x ∣ > 2

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

8 - 2 x < - 2 or 8 - 2 x > 2

8 - 2 x < - 2 or 8 - 2 x > 2

x < 3 or x > 5

15 p + 3 (p - 1) > 3 (2^{3})

2 x^{2} + x + 9 = 0

∣ x + 2 ∣ > - 5

7 x = 3 x

3 x^{2} + x + 5 = 0