What are the solutions to the equation x^2-12x-4=0 ?

The solutions to the equation x^2-12x-4=0 are x=2(3+sqrt(10)),x=2(3-sqrt(10))

Find the zeros of x^2-12x-4=0

The zeros of x^2-12x-4=0 are x=2(3+sqrt(10)),x=2(3-sqrt(10))

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x^{2} - 12 x - 4 = 0

x = 2 (3 + 10), x = 2 (3 - 10)

Decimal Notation

x = 12.32455 \dots, x = - 0.32455 \dots

Solution steps

x^{2} - 12 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 4) = 410

x_{1, 2} = \frac{- ( - 12 ) \pm 4 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 10}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 10}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 10}{2 \cdot 1} : 2 (3 + 10)

x = \frac{- ( - 12 ) - 4 10}{2 \cdot 1} : 2 (3 - 10)

The solutions to the quadratic equation are:

x = 2 (3 + 10), x = 2 (3 - 10)

\frac{- x}{4} = \frac{- x}{3} + \frac{1}{4}

\frac{4 15}{2 3}

- 5 = - 3 (2) + b

3 x^{2} + x y - 2 y^{2}

2 p^{3} - 50 p

What are the solutions to the equation x^2-12x-4=0 ?
The solutions to the equation x^2-12x-4=0 are x=2(3+sqrt(10)),x=2(3-sqrt(10))
Find the zeros of x^2-12x-4=0
The zeros of x^2-12x-4=0 are x=2(3+sqrt(10)),x=2(3-sqrt(10))