Putting it Together: Graph Linear Equations and Inequalities
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Years since 2009 | Minutes |
---|---|
[latex]0[/latex] | [latex]8.5[/latex] |
[latex]1[/latex] | [latex]9.25[/latex] |
[latex]2[/latex] | [latex]10[/latex] |
[latex]3[/latex] | [latex]10.75[/latex] |
[latex]4[/latex] | [latex]11.5[/latex] |
[latex]5[/latex] | [latex]12.25[/latex] |
[latex]6[/latex] | [latex]13[/latex] |
The Cartesian Coordinate Plane
Joan remembers that the coordinate plane gives graphs structure and meaning. A straight line on a page won't tell Devon's readers much. Joan draws the axes and labels the horizontal one "Years Since [latex]2009[/latex]," because that's the first data point they have. Then Devon labels the vertical axis from [latex]1[/latex] to [latex]18[/latex] because the minute data ranges from [latex]8.5[/latex] to [latex]13[/latex] minutes, and that will give room on either side.


Finding the Equation
Joan remembers that knowing the slope and y-intercept of a line can help her write the equation of the line. She realizes they know the y-intercept: [latex](0,8.5)[/latex], and just need the slope. Joan checks her math notes to find the definition of slope, and uses two data points to calculate it:[latex]\begin{array}{l} \text{Slope}=\dfrac{\text{rise}}{\text{run}}\\\\m=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}\\\\m=\dfrac{{11.5}-{10.75}}{{4}-{3}}\\\\m=\dfrac{{0.75}}{{1}} = 0.75\end{array}[/latex]
Now Devon and Joan have the two pieces of information they need to write the equation of the line that represents how many minutes of commercials will be in one hour of TV in any year before or after [latex]2009[/latex]. First, they choose some variables: x = the year and y = the number of minutes. They then substitute the values for m and b into the slope-intercept form of a line:[latex]\begin{array}{l}{ y }= {m x} + {b}\\{ y }= {0.75 x} + {8.5}\end{array}[/latex]
Remembering that the whole point of this exercise was to answer Devon's reader's question, they then figure out what [latex]10[/latex] years from now would be in relation to [latex]0[/latex] representing [latex]2009[/latex] on your graph. If [latex]10[/latex] years from now is [latex]2026[/latex], then it's [latex]17[/latex] years from [latex]2009[/latex]. The x value they need in order to answer the question is [latex]17[/latex].[latex]\begin{array}{l}{ y }= {0.75 (17)} + {8.5}\\\\{ y }= {12.75} + {8.5}\\\\{ y }= {21.25}\end{array}[/latex]
Devon and Joan have a new data point: [latex](17,21.25)[/latex]. This means that in [latex]2026[/latex] there will be more than [latex]20[/latex] minutes of commercials in one hour of TV. Yuck!