Which Finance Formula to Use?
Introduction
Now that we have surveyed the basic kinds of finance calculations that are used, it may not always be obvious which one to use when you are given a problem to solve. In this section, we review our finance formulas and discuss some hints on deciding which equation to use, based on the wording of the problem.Learning Outcomes
- Determine which financial mathematics formula to use for a given scenario
Determining the Correct Formula
Loans
The easiest types of problems to identify are loans. Loan problems almost always include words like loan, amortize (the fancy word for loans), finance (i.e. a car), or mortgage (a home loan). Look for words like monthly or annual payment. The loan formula assumes that you make loan payments on a regular schedule (every month, year, quarter, etc.) and are paying interest on the loan.Loans Formula
[latex-display]P_{0}=\frac{d\left(1-\left(1+\frac{r}{k}\right)^{-Nk}\right)}{\left(\frac{r}{k}\right)}[/latex-display]- P0 is the balance in the account at the beginning (the principal, or amount of the loan).
- d is your loan payment (your monthly payment, annual payment, etc)
- r is the annual interest rate in decimal form.
- k is the number of compounding periods in one year.
- N is the length of the loan, in years.
Interest-Bearing Accounts
Accounts that gain interest fall into two main categories. The first is on where you put money in an account once and let it sit, the other is where you make regular payments or withdrawals from the account as in a retirement account. Category 1: You make a one-time deposit and let the money sit and earn interest. For most accounts in this category, the interest will be Compounding. This will be stated explicitly in the problem.COMPOUND INTEREST
[latex-display]P_{N}=P_{0}\left(1+\frac{r}{k}\right)^{Nk}[/latex-display]- PN is the balance in the account after N years.
- P0 is the starting balance of the account (also called initial deposit, or principal)
- r is the annual interest rate in decimal form
- k is the number of compounding periods in one year
- If the compounding is done annually (once a year), k = 1.
- If the compounding is done quarterly, k = 4.
- If the compounding is done monthly, k = 12.
- If the compounding is done daily, k = 365.
SIMPLE INTEREST OVER TIME
[latex-display]\begin{align}&I={{P}_{0}}rt\\&A={{P}_{0}}+I={{P}_{0}}+{{P}_{0}}rt={{P}_{0}}(1+rt)\\\end{align}[/latex-display]- I is the interest
- A is the end amount: principal plus interest
- [latex]\begin{align}{{P}_{0}}\\\end{align}[/latex] is the principal (starting amount)
- r is the interest rate in decimal form
- t is time
ANNUITY FORMULA
[latex-display]P_{N}=\frac{d\left(\left(1+\frac{r}{k}\right)^{Nk}-1\right)}{\left(\frac{r}{k}\right)}[/latex-display]- PN is the balance in the account after N years.
- d is the regular deposit (the amount you deposit each year, each month, etc.)
- r is the annual interest rate in decimal form.
- k is the number of compounding periods in one year.
PAYOUT ANNUITY FORMULA
[latex-display]P_{0}=\frac{d\left(1-\left(1+\frac{r}{k}\right)^{-Nk}\right)}{\left(\frac{r}{k}\right)}[/latex-display]- P0 is the balance in the account at the beginning (starting amount, or principal).
- d is the regular withdrawal (the amount you take out each year, each month, etc.)
- r is the annual interest rate (in decimal form. Example: 5% = 0.05)
- k is the number of compounding periods in one year.
- N is the number of years we plan to take withdrawals
Try It
For each of the following scenarios, determine if it is a compound interest problem, a savings annuity problem, a payout annuity problem, or a loans problem. Then, try using an Excel spreadsheet (or online loan/annuity calculator) to solve each problem.- Marcy received an inheritance of $20,000, and invested it at 6% interest. She is going to use it for college, withdrawing money for tuition and expenses each quarter. How much can she take out each quarter if she has 3 years of school left?
Answer: This is a payout annuity problem. She can pull out $1833.60 a quarter.
- Paul wants to buy a new car. Rather than take out a loan, he decides to save $200 a month in an account earning 3% interest compounded monthly. How much will he have saved up after 3 years?
Answer: This is a savings annuity problem. He will have saved up $7,524.11
- Keisha is managing investments for a non-profit company. They want to invest some money in an account earning 5% interest compounded annually with the goal to have $30,000 in the account in 6 years. How much should Keisha deposit into the account?
Answer: This is compound interest problem. She would need to deposit $22,386.46.
- Miao is going to finance new office equipment at a 2% rate over a 4 year term. If she can afford monthly payments of $100, how much new equipment can she buy?
Answer: This is a loans problem. She can buy $4,609.33 of new equipment
- How much would you need to save every month in an account earning 4% interest to have $5,000 saved up in two years?
Answer: This is a savings annuity problem. You would need to save $200.46 each month
End of Section--No Online HW for this Section
Go to Section 3.6
Licenses & Attributions
CC licensed content, Original
- Revision and Adaptation. Provided by: Lumen Learning License: CC BY: Attribution.
CC licensed content, Shared previously
- Which Equation to Use?. Authored by: David Lippman. Located at: http://www.opentextbookstore.com/mathinsociety/. License: CC BY-SA: Attribution-ShareAlike.
- Identifying type of finance problem. Authored by: OCLPhase2's channel. License: Public Domain: No Known Copyright.
- Multistage finance problem. Authored by: OCLPhase2's channel. License: CC BY: Attribution.
- Question ID 67287, 67306, 67133. Authored by: Abert, Rex. License: CC BY: Attribution. License terms: IMathAS Community License CC-BY + GPL.