J1.03: Section 1 Part 2
Example 1: Fitting an exponential model to find the growth rate
Use this data from the first 10 U.S. censuses to make an exponential model of U.S. population growth, then use that model to answer these questions: [Use the Exponential Model worksheet in Models.xls.]- Does an exponential model fit this data well? How do you know?
- What was the average annual growth rate during this period?
- What population does the model predict for 1900? For 2000?
Solution procedure:
[1] Redefine the input variable to “Years since 1780”, adjusting the x values in column A to start at 0.Year | Population (millions) |
1780 | 2.8 |
1790 | 3.9 |
1800 | 5.3 |
1810 | 7.2 |
1820 | 9.6 |
1830 | 12.9 |
1840 | 17.1 |
1850 | 23.2 |
1860 | 31.4 |
1870 | 39.8 |
- Set G3 to 2.8, the first value in the table. (We can later adjust this to reduce standard deviation).
- Set G4 to 0.01 (which is 1%), then adjust it until the shape of the model is close to that of the data at about 0.03 (which is 3%).
A | B | C | D | E | F | G | H | |||
1 | x | y data | y model | Data-Model | Exponential model: y = a * (1+r)^x | |||||
2 | Year-1780 | Height | Prediction | deviation | y = 2.8 * (1+0.03)^x | |||||
3 | 0 | 2.8 | 2.80 | 0.0000 | 2.8 | a: Initial value at x=0 | ||||
4 | 10 | 3.9 | 3.76 | 0.1370 |
|
0.03 | r: Growth rate | |||
5 | 20 | 5.3 | 5.06 | 0.2429 | ||||||
6 | 30 | 7.2 | 6.80 | 0.4037 | ||||||
7 | 40 | 9.6 | 9.13 | 0.4663 | Model and data value counts | |||||
8 | 50 | 12.9 | 12.27 | 0.6251 | 2 | Number of parameters | ||||
9 | 60 | 17.1 | 16.50 | 0.6035 | 10 | Number of data points | ||||
10 | 70 | 23.2 | 22.17 | 1.0301 | ||||||
11 | 80 | 31.4 | 29.79 | 1.6055 | Goodness of fit of this model | |||||
12 | 90 | 39.8 | 40.04 | -0.2413 | 4.910062 | Sum of squared deviat | ||||
13 | 120 | 97.19 | 0.783427 | Standard deviation | ||||||
14 | 220 | 1867.87 |
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- Mathematics for Modeling. Authored by: Mary Parker and Hunter Ellinger. License: CC BY: Attribution.