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Popular Word Problems >

The sum of the squares of three consecutive odd integers is 363. Find the numbers

Solução

T h e s u m o f t h e s q u a res o f t h ree co n sec u t i v e o dd in t e g ers i s 363. F in d t h e n u mb ers

Solução

Sem solu \overset{c}{\c} \tilde{a} o

Passos da solução

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

x^{2} + (x + 2)^{2} + (x + 4)^{2} = 363

Resolver

x^{2} + (x + 2)^{2} + (x + 4)^{2} = 363 : x = \frac{- 6 + 1065}{3}, x = - \frac{6 + 1065}{3}

Inserir

x = \frac{- 6 + 1065}{3} :

Inválido

Inserir

x = - \frac{6 + 1065}{3} :

Inválido

Sem solu \overset{c}{\c} \tilde{a} o

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