The sum of the squares of three consecutive odd integers is 363. Find the numbers

解

T h e s u m o f t h e s q u a res o f t h ree co n sec u t i v e o dd in t e g ers i s 363. F in d t h e n u mb ers

解なし

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

x^{2} + (x + 2)^{2} + (x + 4)^{2} = 363

解く

x^{2} + (x + 2)^{2} + (x + 4)^{2} = 363 : x = \frac{- 6 + 1065}{3}, x = - \frac{6 + 1065}{3}

挿入

x = \frac{- 6 + 1065}{3} :

無効

挿入

x = - \frac{6 + 1065}{3} :

無効

解なし