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인기 있는 삼각법 >

2tan(60-x)=tan(x)

해법

2 tan (60 - x) = tan (x)

해법

x = - 1.46681 \dots + πn, x = 0.20575 \dots + πn

+1

도

x = - 84.04237 \dots^{\circ} + 18 0^{\circ} n, x = 11.78914 \dots^{\circ} + 18 0^{\circ} n

솔루션 단계

2 tan (60 - x) = tan (x)

빼다

tan (x)

양쪽에서

2 tan (60 - x) - tan (x) = 0

삼각성을 사용하여 다시 쓰기

- tan (x) + 2 tan (60 - x)

각도 차이 식별 사용:

tan (s - t) = \frac{tan ( s ) - tan ( t )}{1 + tan ( s ) tan ( t )}

= - tan (x) + 2 \cdot \frac{tan ( 60 ) - tan ( x )}{1 + tan ( 60 ) tan ( x )}

- tan (x) + 2 \cdot \frac{tan ( 60 ) - tan ( x )}{1 + tan ( 60 ) tan ( x )}

간소화하다 :

\frac{2 tan ( 60 ) - 3 tan ( x ) - tan ( 60 ) tan ^{2} ( x )}{1 + tan ( 60 ) tan ( x )}

- tan (x) + 2 \cdot \frac{tan ( 60 ) - tan ( x )}{1 + tan ( 60 ) tan ( x )}

2 \cdot \frac{tan ( 60 ) - tan ( x )}{1 + tan ( 60 ) tan ( x )}

곱하다

: \frac{2 ( - tan ( x ) + tan ( 60 ) )}{1 + tan ( 60 ) tan ( x )}

2 \cdot \frac{tan ( 60 ) - tan ( x )}{1 + tan ( 60 ) tan ( x )}

다중 분수:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( tan ( 60 ) - tan ( x ) ) \cdot 2}{1 + tan ( 60 ) tan ( x )}

= - tan (x) + \frac{2 ( - tan ( x ) + tan ( 60 ) )}{tan ( 60 ) tan ( x ) + 1}

요소를 분수로 변환:

tan (x) = \frac{tan ( x ) ( 1 + tan ( 60 ) tan ( x ) )}{1 + tan ( 60 ) tan ( x )}

= \frac{( tan ( 60 ) - tan ( x ) ) \cdot 2}{1 + tan ( 60 ) tan ( x )} - \frac{tan ( x ) ( 1 + tan ( 60 ) tan ( x ) )}{1 + tan ( 60 ) tan ( x )}

분모가 같기 때문에, 분수를 합친다:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( tan ( 60 ) - tan ( x ) ) \cdot 2 - tan ( x ) ( 1 + tan ( 60 ) tan ( x ) )}{1 + tan ( 60 ) tan ( x )}

(tan (60) - tan (x)) \cdot 2 - tan (x) (1 + tan (60) tan (x))

확대한다:

2 tan (60) - 3 tan (x) - tan (60) tan^{2} (x)

(tan (60) - tan (x)) \cdot 2 - tan (x) (1 + tan (60) tan (x))

= 2 (tan (60) - tan (x)) - tan (x) (1 + tan (60) tan (x))

2 (tan (60) - tan (x))

확대한다:

2 tan (60) - 2 tan (x)

2 (tan (60) - tan (x))

분배 법칙 적용:

a (b - c) = ab - a c

a = 2, b = tan (60), c = tan (x)

= 2 tan (60) - 2 tan (x)

= 2 tan (60) - 2 tan (x) - tan (x) (1 + tan (60) tan (x))

- tan (x) (1 + tan (60) tan (x))

확대한다:

- tan (x) - tan (60) tan^{2} (x)

- tan (x) (1 + tan (60) tan (x))

분배 법칙 적용:

a (b + c) = ab + a c

a = - tan (x), b = 1, c = tan (60) tan (x)

= - tan (x) \cdot 1 + (- tan (x)) tan (60) tan (x)

마이너스 플러스 규칙 적용

+ (- a) = - a

= - 1 \cdot tan (x) - tan (60) tan (x) tan (x)

- 1 \cdot tan (x) - tan (60) tan (x) tan (x)

단순화하세요:

- tan (x) - tan (60) tan^{2} (x)

- 1 \cdot tan (x) - tan (60) tan (x) tan (x)

1 \cdot tan (x) = tan (x)

1 \cdot tan (x)

곱하다:

1 \cdot tan (x) = tan (x)

= tan (x)

tan (60) tan (x) tan (x) = tan (60) tan^{2} (x)

tan (60) tan (x) tan (x)

지수 규칙 적용:

a^{b} \cdot a^{c} = a^{b + c}

tan (x) tan (x) = tan^{1 + 1} (x)

= tan (60) tan^{1 + 1} (x)

숫자 추가:

1 + 1 = 2

= tan (60) tan^{2} (x)

= - tan (x) - tan (60) tan^{2} (x)

= - tan (x) - tan (60) tan^{2} (x)

= 2 tan (60) - 2 tan (x) - tan (x) - tan (60) tan^{2} (x)

유사 요소 추가:

- 2 tan (x) - tan (x) = - 3 tan (x)

= 2 tan (60) - 3 tan (x) - tan (60) tan^{2} (x)

= \frac{2 tan ( 60 ) - 3 tan ( x ) - tan ( 60 ) tan ^{2} ( x )}{1 + tan ( 60 ) tan ( x )}

= \frac{2 tan ( 60 ) - 3 tan ( x ) - tan ( 60 ) tan ^{2} ( x )}{1 + tan ( 60 ) tan ( x )}

\frac{2 tan ( 60 ) - 3 tan ( x ) - tan ( 60 ) tan ^{2} ( x )}{1 + tan ( 60 ) tan ( x )} = 0

대체로 해결

\frac{2 tan ( 60 ) - 3 tan ( x ) - tan ( 60 ) tan ^{2} ( x )}{1 + tan ( 60 ) tan ( x )} = 0

하게:

tan (x) = u

\frac{2 tan ( 60 ) - 3 u - tan ( 60 ) u ^{2}}{1 + tan ( 60 ) u} = 0

\frac{2 tan ( 60 ) - 3 u - tan ( 60 ) u ^{2}}{1 + tan ( 60 ) u} = 0 : u = - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}, u = \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

\frac{2 tan ( 60 ) - 3 u - tan ( 60 ) u ^{2}}{1 + tan ( 60 ) u} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 tan (60) - 3 u - tan (60) u^{2} = 0

2 tan (60) - 3 u - tan (60) u^{2} = 0

해결 :

u = - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}, u = \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

2 tan (60) - 3 u - tan (60) u^{2} = 0

표준 양식으로 작성

a x^{2} + b x + c = 0

- tan (60) u^{2} - 3 u + 2 tan (60) = 0

쿼드 공식으로 해결

- tan (60) u^{2} - 3 u + 2 tan (60) = 0

4차 방정식 공식:

위해서

a = - tan (60), b = - 3, c = 2 tan (60)

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - tan ( 60 ) ) \cdot 2 tan ( 60 )}{2 ( - tan ( 60 ) )}

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - tan ( 60 ) ) \cdot 2 tan ( 60 )}{2 ( - tan ( 60 ) )}

(- 3)^{2} - 4 (- tan (60)) \cdot 2 tan (60) = 9 + 8 tan^{2} (60)

(- 3)^{2} - 4 (- tan (60)) \cdot 2 tan (60)

규칙 적용

- (- a) = a

= (- 3)^{2} + 4 tan (60) \cdot 2 tan (60)

(- 3)^{2} = 3^{2}

(- 3)^{2}

지수 규칙 적용:

(- a)^{n} = a^{n},

이면

n

균등하다

(- 3)^{2} = 3^{2}

= 3^{2}

4 tan (60) \cdot 2 tan (60) = 8 tan^{2} (60)

4 tan (60) \cdot 2 tan (60)

숫자를 곱하시오:

4 \cdot 2 = 8

= 8 tan (60) tan (60)

지수 규칙 적용:

a^{b} \cdot a^{c} = a^{b + c}

tan (60) tan (60) = tan^{1 + 1} (60)

= 8 tan^{1 + 1} (60)

숫자 추가:

1 + 1 = 2

= 8 tan^{2} (60)

= 3^{2} + 8 tan^{2} (60)

3^{2} = 9

= 9 + 8 tan^{2} (60)

u_{1, 2} = \frac{- ( - 3 ) \pm 9 + 8 tan ^{2} ( 60 )}{2 ( - tan ( 60 ) )}

솔루션 분리

u_{1} = \frac{- ( - 3 ) + 9 + 8 tan ^{2} ( 60 )}{2 ( - tan ( 60 ) )}, u_{2} = \frac{- ( - 3 ) - 9 + 8 tan ^{2} ( 60 )}{2 ( - tan ( 60 ) )}

u = \frac{- ( - 3 ) + 9 + 8 tan ^{2} ( 60 )}{2 ( - tan ( 60 ) )} : - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}

\frac{- ( - 3 ) + 9 + 8 tan ^{2} ( 60 )}{2 ( - tan ( 60 ) )}

괄호 제거:

(- a) = - a, - (- a) = a

= \frac{3 + 9 + 8 tan ^{2} ( 60 )}{- 2 tan ( 60 )}

분수 규칙 적용:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}

u = \frac{- ( - 3 ) - 9 + 8 tan ^{2} ( 60 )}{2 ( - tan ( 60 ) )} : \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

\frac{- ( - 3 ) - 9 + 8 tan ^{2} ( 60 )}{2 ( - tan ( 60 ) )}

괄호 제거:

(- a) = - a, - (- a) = a

= \frac{3 - 9 + 8 tan ^{2} ( 60 )}{- 2 tan ( 60 )}

분수 규칙 적용:

\frac{- a}{- b} = \frac{a}{b}

3 - 9 + 8 tan^{2} (60) = - (8 tan^{2} (60) + 9 - 3)

= \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

2차 방정식의 해는 다음과 같다:

u = - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}, u = \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

u = - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}, u = \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

솔루션 확인

정의되지 않은 (특이점) 점 찾기:

u = - \frac{1}{tan ( 60 )}

의 분모를 취하라

\frac{2 tan ( 60 ) - 3 u - tan ( 60 ) u ^{2}}{1 + tan ( 60 ) u}

그리고 0과 비교한다

1 + tan (60) u = 0

해결 :

u = - \frac{1}{tan ( 60 )}

1 + tan (60) u = 0

1

를 오른쪽으로 이동

1 + tan (60) u = 0

빼다

1

양쪽에서

1 + tan (60) u - 1 = 0 - 1

단순화

tan (60) u = - 1

tan (60) u = - 1

양쪽을 다음으로 나눕니다

tan (60)

tan (60) u = - 1

양쪽을 다음으로 나눕니다

tan (60)

\frac{tan ( 60 ) u}{tan ( 60 )} = \frac{- 1}{tan ( 60 )}

단순화

u = - \frac{1}{tan ( 60 )}

u = - \frac{1}{tan ( 60 )}

다음 지점은 정의되지 않았습니다

u = - \frac{1}{tan ( 60 )}

정의되지 않은 점을 솔루션과 결합:

u = - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}, u = \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

뒤로 대체

u = tan (x)

tan (x) = - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}, tan (x) = \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

tan (x) = - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}, tan (x) = \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

tan (x) = - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )} : x = arctan (- \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}) + πn

tan (x) = - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}

트리거 역속성 적용

tan (x) = - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}

일반 솔루션

tan (x) = - \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

x = arctan (- \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}) + πn

x = arctan (- \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}) + πn

tan (x) = \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )} : x = arctan (\frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}) + πn

tan (x) = \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

트리거 역속성 적용

tan (x) = \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

일반 솔루션

tan (x) = \frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}

tan (x) = a \Rightarrow x = arctan (a) + πn

x = arctan (\frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}) + πn

x = arctan (\frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}) + πn

모든 솔루션 결합

x = arctan (- \frac{3 + 9 + 8 tan ^{2} ( 60 )}{2 tan ( 60 )}) + πn, x = arctan (\frac{8 tan ^{2} ( 60 ) + 9 - 3}{2 tan ( 60 )}) + πn

해를 10진수 형식으로 표시

x = - 1.46681 \dots + πn, x = 0.20575 \dots + πn

그래프

인기 있는 예

cos (x) = - 0.71

tan (α) = \frac{8}{10}

sin(2x)+sqrt(2)*cos(x)=0

sin (2 x) + 2 \cdot cos (x) = 0

(6.7)/(sin(33))=(5.4)/(sin(A))

\frac{6.7}{sin ( 3 3 ^{\circ} )} = \frac{5.4}{sin ( A )}

2 - 3 sin (θ) = 0