What is the general solution for solvefor x,tan^2(x)=1 ?

The general solution for solvefor x,tan^2(x)=1 is x= pi/4+pin,x=(3pi)/4+pin

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solvefor x,tan^2(x)=1

solve for

x, tan^{2} (x) = 1

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

tan^{2} (x) = 1

Solve by substitution

tan (x) = 1, tan (x) = - 1

tan (x) = 1 : x = \frac{π}{4} + πn

tan (x) = - 1 : x = \frac{3 π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

x, tan^{2} (x) = 2

x, \frac{p}{q} = sin^{2} (x)

cos (2 x) = 1 - 2 (\frac{3}{5})^{2}

sin (θ + \frac{π}{3}) = \frac{1}{2}

4 sin^{2} (x) = 5 - 4 cos (x), 0 \leq x < 2 π

What is the general solution for solvefor x,tan^2(x)=1 ?
The general solution for solvefor x,tan^2(x)=1 is x= pi/4+pin,x=(3pi)/4+pin