What is the general solution for solvefor x,cos^2(x)=sin^2(x) ?

The general solution for solvefor x,cos^2(x)=sin^2(x) is x= pi/4+pin,x=(3pi)/4+pin

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solvefor x,cos^2(x)=sin^2(x)

solve for

x, cos^{2} (x) = sin^{2} (x)

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

cos^{2} (x) = sin^{2} (x)

Subtract

sin^{2} (x)

from both sides

cos^{2} (x) - sin^{2} (x) = 0

Rewrite using trig identities

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

3 cot (x) - 1 = cot^{2} (x)

sin (x) = - 0.974

sin (x) = - 0.978

cos (t) = \frac{15}{17}

cos (x) = - \frac{3}{2 3}

What is the general solution for solvefor x,cos^2(x)=sin^2(x) ?
The general solution for solvefor x,cos^2(x)=sin^2(x) is x= pi/4+pin,x=(3pi)/4+pin