What is the general solution for solvefor T,y=sin(2T) ?

The general solution for solvefor T,y=sin(2T) is T=(arcsin(y))/2+pin,T= pi/2+(arcsin(-y))/2+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor T,y=sin(2T)

solve for

T, y = sin (2 T)

T = \frac{arcsin ( y )}{2} + πn, T = \frac{π}{2} + \frac{arcsin ( - y )}{2} + πn

Solution steps

y = sin (2 T)

Switch sides

sin (2 T) = y

Apply trig inverse properties

2 T = arcsin (y) + 2 πn, 2 T = π + arcsin (- y) + 2 πn

Solve

2 T = arcsin (y) + 2 πn : T = \frac{arcsin ( y )}{2} + πn

Solve

2 T = π + arcsin (- y) + 2 πn : T = \frac{π}{2} + \frac{arcsin ( - y )}{2} + πn

T = \frac{arcsin ( y )}{2} + πn, T = \frac{π}{2} + \frac{arcsin ( - y )}{2} + πn

sin (4 7^{\circ}) = cos (x)

0.82 = 0.102 cos (3.715 t)

sin^{2} (x) + 0.49 = 1

6 cos^{2} (θ) + sin^{2} (θ) = 4

15 sin (3 0^{\circ}) = 10 sin (x)

What is the general solution for solvefor T,y=sin(2T) ?
The general solution for solvefor T,y=sin(2T) is T=(arcsin(y))/2+pin,T= pi/2+(arcsin(-y))/2+pin