What is the general solution for 13/12 =cosh(x/(120)) ?

The general solution for 13/12 =cosh(x/(120)) is x=120ln(3/2)

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13/12 =cosh(x/(120))

\frac{13}{12} = cosh (\frac{x}{120})

x = 120 ln (\frac{3}{2})

Solution steps

\frac{13}{12} = cosh (\frac{x}{120})

Switch sides

cosh (\frac{x}{120}) = \frac{13}{12}

Rewrite using trig identities

\frac{e ^{\frac{x}{120}} + e ^{- \frac{x}{120}}}{2} = \frac{13}{12}

\frac{e ^{\frac{x}{120}} + e ^{- \frac{x}{120}}}{2} = \frac{13}{12} : x = 120 ln (\frac{3}{2})

x = 120 ln (\frac{3}{2})

θ, r = - \frac{3}{r cos ( θ )}

sin^{2} (x) + sin (2 x) = 1

T, y = sin (2 T)

sin (4 7^{\circ}) = cos (x)

0.82 = 0.102 cos (3.715 t)

What is the general solution for 13/12 =cosh(x/(120)) ?
The general solution for 13/12 =cosh(x/(120)) is x=120ln(3/2)