What is the general solution for 2sqrt(2)sin(x)+sec(x)=0 ?

The general solution for 2sqrt(2)sin(x)+sec(x)=0 is x=(5pi)/8+pin,x=(7pi)/8+pin

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2sqrt(2)sin(x)+sec(x)=0

Solution

22 sin (x) + sec (x) = 0

Solution

x = \frac{5 π}{8} + πn, x = \frac{7 π}{8} + πn

Degrees

x = 112. 5^{\circ} + 18 0^{\circ} n, x = 157. 5^{\circ} + 18 0^{\circ} n

Solution steps

22 sin (x) + sec (x) = 0

Express with sin, cos

sec (x) + 2 sin (x) 2

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= \frac{1}{cos ( x )} + 2 sin (x) 2

Simplify

\frac{1}{cos ( x )} + 2 sin (x) 2 : \frac{1 + 2 2 sin ( x ) cos ( x )}{cos ( x )}

\frac{1}{cos ( x )} + 2 sin (x) 2

Convert element to fraction:

22 sin (x) = \frac{2 sin ( x ) 2 cos ( x )}{cos ( x )}

= \frac{1}{cos ( x )} + \frac{2 sin ( x ) 2 cos ( x )}{cos ( x )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 2 sin ( x ) 2 cos ( x )}{cos ( x )}

= \frac{1 + 2 2 sin ( x ) cos ( x )}{cos ( x )}

\frac{1 + 2 cos ( x ) sin ( x ) 2}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

1 + 2 cos (x) sin (x) 2 = 0

Rewrite using trig identities

1 + 2 cos (x) sin (x) 2

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= 1 + sin (2 x) 2

1 + sin (2 x) 2 = 0

Move

1

to the right side

1 + sin (2 x) 2 = 0

Subtract

1

from both sides

1 + sin (2 x) 2 - 1 = 0 - 1

Simplify

sin (2 x) 2 = - 1

sin (2 x) 2 = - 1

Divide both sides by

2

sin (2 x) 2 = - 1

Divide both sides by

2

\frac{sin ( 2 x ) 2}{2} = \frac{- 1}{2}

Simplify

\frac{sin ( 2 x ) 2}{2} = \frac{- 1}{2}

Simplify

\frac{sin ( 2 x ) 2}{2} : sin (2 x)

\frac{sin ( 2 x ) 2}{2}

Cancel the common factor:

2

= sin (2 x)

Simplify

\frac{- 1}{2} : - \frac{2}{2}

\frac{- 1}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2}

Rationalize

- \frac{1}{2} : - \frac{2}{2}

- \frac{1}{2}

Multiply by the conjugate

\frac{2}{2}

= - \frac{1 \cdot 2}{2 2}

1 \cdot 2 = 2

22 = 2

22

Apply radical rule:

a a = a

22 = 2

= 2

= - \frac{2}{2}

= - \frac{2}{2}

sin (2 x) = - \frac{2}{2}

sin (2 x) = - \frac{2}{2}

sin (2 x) = - \frac{2}{2}

General solutions for

sin (2 x) = - \frac{2}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

2 x = \frac{5 π}{4} + 2 πn, 2 x = \frac{7 π}{4} + 2 πn

2 x = \frac{5 π}{4} + 2 πn, 2 x = \frac{7 π}{4} + 2 πn

Solve

2 x = \frac{5 π}{4} + 2 πn : x = \frac{5 π}{8} + πn

2 x = \frac{5 π}{4} + 2 πn

Divide both sides by

2

2 x = \frac{5 π}{4} + 2 πn

Divide both sides by

2

\frac{2 x}{2} = \frac{\frac{5 π}{4}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} = \frac{\frac{5 π}{4}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{\frac{5 π}{4}}{2} + \frac{2 πn}{2} : \frac{5 π}{8} + πn

\frac{\frac{5 π}{4}}{2} + \frac{2 πn}{2}

\frac{\frac{5 π}{4}}{2} = \frac{5 π}{8}

\frac{\frac{5 π}{4}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{4 \cdot 2}

Multiply the numbers:

4 \cdot 2 = 8

= \frac{5 π}{8}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

= \frac{5 π}{8} + πn

x = \frac{5 π}{8} + πn

x = \frac{5 π}{8} + πn

x = \frac{5 π}{8} + πn

Solve

2 x = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{8} + πn

2 x = \frac{7 π}{4} + 2 πn

Divide both sides by

2

2 x = \frac{7 π}{4} + 2 πn

Divide both sides by

2

\frac{2 x}{2} = \frac{\frac{7 π}{4}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} = \frac{\frac{7 π}{4}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{\frac{7 π}{4}}{2} + \frac{2 πn}{2} : \frac{7 π}{8} + πn

\frac{\frac{7 π}{4}}{2} + \frac{2 πn}{2}

\frac{\frac{7 π}{4}}{2} = \frac{7 π}{8}

\frac{\frac{7 π}{4}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{7 π}{4 \cdot 2}

Multiply the numbers:

4 \cdot 2 = 8

= \frac{7 π}{8}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

= \frac{7 π}{8} + πn

x = \frac{7 π}{8} + πn

x = \frac{7 π}{8} + πn

x = \frac{7 π}{8} + πn

x = \frac{5 π}{8} + πn, x = \frac{7 π}{8} + πn

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Frequently Asked Questions (FAQ)

What is the general solution for 2sqrt(2)sin(x)+sec(x)=0 ?
The general solution for 2sqrt(2)sin(x)+sec(x)=0 is x=(5pi)/8+pin,x=(7pi)/8+pin