What is the general solution for 2sin(θ)-3=0 ?

The general solution for 2sin(θ)-3=0 is No Solution for θ\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin(θ)-3=0

2 sin (θ) - 3 = 0

No Solution for θ \in R

Solution steps

2 sin (θ) - 3 = 0

Move

3

to the right side

2 sin (θ) - 3 = 0

Add

3

to both sides

2 sin (θ) - 3 + 3 = 0 + 3

Simplify

2 sin (θ) = 3

2 sin (θ) = 3

Divide both sides by

2

2 sin (θ) = 3

Divide both sides by

2

\frac{2 sin ( θ )}{2} = \frac{3}{2}

Simplify

sin (θ) = \frac{3}{2}

sin (θ) = \frac{3}{2}

- 1 \leq sin (x) \leq 1

No Solution for θ \in R

2 cos^{2} (t) + 7 cos (t) + 5 = 0

cos (x) = \frac{35}{45}

\frac{π}{6} = cos (2 t)

x, 3 tan (2 x) = 1

y, x = 5 \cdot sin (y)

What is the general solution for 2sin(θ)-3=0 ?
The general solution for 2sin(θ)-3=0 is No Solution for θ\in\mathbb{R}