What is the general solution for tan(t)=-12/5 ,(3pi)/2 <t<2pi,sin(t) ?

The general solution for tan(t)=-12/5 ,(3pi)/2 <t<2pi,sin(t) is t=-1.17600…+2pi

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tan(t)=-12/5 ,(3pi)/2 <t<2pi,sin(t)

tan (t) = - \frac{12}{5}, \frac{3 π}{2} < t < 2 π, sin (t)

t = - 1.17600 \dots + 2 π

Degrees

t = 292.61986 \dots^{\circ}

Solution steps

tan (t) = - \frac{12}{5}, \frac{3 π}{2} < t < 2 π, sin (t)

Apply trig inverse properties

tan (t) = - \frac{12}{5}

General solutions for

tan (t) = - \frac{12}{5}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

t = arctan (- \frac{12}{5}) + πn

t = arctan (- \frac{12}{5}) + πn

Solutions for the range

\frac{3 π}{2} < t < 2 π

t = - arctan (\frac{12}{5}) + 2 π

Show solutions in decimal form

t = - 1.17600 \dots + 2 π

tan (6. 5^{2} - a) = 8

- 10 cos (θ) = - 2 - 6 cos (θ)

sin (a) = (\frac{( 8 )}{( 153 )})

2 csc^{2} (x) - 1 = 0

- sec (θ) cot (θ) - sec (θ) = - 2 sec (θ)

What is the general solution for tan(t)=-12/5 ,(3pi)/2 <t<2pi,sin(t) ?
The general solution for tan(t)=-12/5 ,(3pi)/2 <t<2pi,sin(t) is t=-1.17600…+2pi