What is the general solution for tan(2x)=+9/40 ?

The general solution for tan(2x)=+9/40 is x=(0.22131…)/2+(pin)/2

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tan(2x)=+9/40

tan (2 x) = + \frac{9}{40}

x = \frac{0.22131 \dots}{2} + \frac{πn}{2}

Degrees

x = 6.34019 \dots^{\circ} + 9 0^{\circ} n

Solution steps

tan (2 x) = \frac{9}{40}

Apply trig inverse properties

tan (2 x) = \frac{9}{40}

General solutions for

tan (2 x) = + \frac{9}{40}

tan (x) = a \Rightarrow x = arctan (a) + πn

2 x = arctan (\frac{9}{40}) + πn

2 x = arctan (\frac{9}{40}) + πn

Solve

2 x = arctan (\frac{9}{40}) + πn : x = \frac{arctan ( \frac{9}{40} )}{2} + \frac{πn}{2}

2 x = arctan (\frac{9}{40}) + πn

Divide both sides by

2

2 x = arctan (\frac{9}{40}) + πn

Divide both sides by

2

\frac{2 x}{2} = \frac{arctan ( \frac{9}{40} )}{2} + \frac{πn}{2}

Simplify

x = \frac{arctan ( \frac{9}{40} )}{2} + \frac{πn}{2}

x = \frac{arctan ( \frac{9}{40} )}{2} + \frac{πn}{2}

x = \frac{arctan ( \frac{9}{40} )}{2} + \frac{πn}{2}

Show solutions in decimal form

x = \frac{0.22131 \dots}{2} + \frac{πn}{2}

x, y = cos (6 x)

12 cos^{2} (x) - 6 sin (x) - 6 = 0 [360]

sin (θ) = - 0

tan (x) = \frac{15}{12}

6 sin (θ) + 3 sin (θ) tan (θ) = 3 sin (θ)

What is the general solution for tan(2x)=+9/40 ?
The general solution for tan(2x)=+9/40 is x=(0.22131…)/2+(pin)/2