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Popular Trigonometry >

117.72sin(θ)-35.316cos(θ)-12.5=0

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Solution

117.72sin(θ)−35.316cos(θ)−12.5=0

Solution

θ=0.39333…+2πn,θ=π+0.18957…+2πn
+1
Degrees
θ=22.53666…∘+360∘n,θ=190.86182…∘+360∘n
Solution steps
117.72sin(θ)−35.316cos(θ)−12.5=0
Add 35.316cos(θ) to both sides117.72sin(θ)−12.5=35.316cos(θ)
Square both sides(117.72sin(θ)−12.5)2=(35.316cos(θ))2
Subtract (35.316cos(θ))2 from both sides(117.72sin(θ)−12.5)2−1247.219856cos2(θ)=0
Rewrite using trig identities
(−12.5+117.72sin(θ))2−1247.219856cos2(θ)
Use the Pythagorean identity: cos2(x)+sin2(x)=1cos2(x)=1−sin2(x)=(−12.5+117.72sin(θ))2−1247.219856(1−sin2(θ))
Simplify (−12.5+117.72sin(θ))2−1247.219856(1−sin2(θ)):15105.218256sin2(θ)−2943sin(θ)−1090.969856
(−12.5+117.72sin(θ))2−1247.219856(1−sin2(θ))
(−12.5+117.72sin(θ))2:156.25−2943sin(θ)+13857.9984sin2(θ)
Apply Perfect Square Formula: (a+b)2=a2+2ab+b2a=−12.5,b=117.72sin(θ)
=(−12.5)2+2(−12.5)⋅117.72sin(θ)+(117.72sin(θ))2
Simplify (−12.5)2+2(−12.5)⋅117.72sin(θ)+(117.72sin(θ))2:156.25−2943sin(θ)+13857.9984sin2(θ)
(−12.5)2+2(−12.5)⋅117.72sin(θ)+(117.72sin(θ))2
Remove parentheses: (−a)=−a=(−12.5)2−2⋅12.5⋅117.72sin(θ)+(117.72sin(θ))2
(−12.5)2=156.25
(−12.5)2
Apply exponent rule: (−a)n=an,if n is even(−12.5)2=12.52=12.52
12.52=156.25=156.25
2⋅12.5⋅117.72sin(θ)=2943sin(θ)
2⋅12.5⋅117.72sin(θ)
Multiply the numbers: 2⋅12.5⋅117.72=2943=2943sin(θ)
(117.72sin(θ))2=13857.9984sin2(θ)
(117.72sin(θ))2
Apply exponent rule: (a⋅b)n=anbn=117.722sin2(θ)
117.722=13857.9984=13857.9984sin2(θ)
=156.25−2943sin(θ)+13857.9984sin2(θ)
=156.25−2943sin(θ)+13857.9984sin2(θ)
=156.25−2943sin(θ)+13857.9984sin2(θ)−1247.219856(1−sin2(θ))
Expand −1247.219856(1−sin2(θ)):−1247.219856+1247.219856sin2(θ)
−1247.219856(1−sin2(θ))
Apply the distributive law: a(b−c)=ab−aca=−1247.219856,b=1,c=sin2(θ)=−1247.219856⋅1−(−1247.219856)sin2(θ)
Apply minus-plus rules−(−a)=a=−1⋅1247.219856+1247.219856sin2(θ)
Multiply the numbers: 1⋅1247.219856=1247.219856=−1247.219856+1247.219856sin2(θ)
=156.25−2943sin(θ)+13857.9984sin2(θ)−1247.219856+1247.219856sin2(θ)
Simplify 156.25−2943sin(θ)+13857.9984sin2(θ)−1247.219856+1247.219856sin2(θ):15105.218256sin2(θ)−2943sin(θ)−1090.969856
156.25−2943sin(θ)+13857.9984sin2(θ)−1247.219856+1247.219856sin2(θ)
Group like terms=−2943sin(θ)+13857.9984sin2(θ)+1247.219856sin2(θ)+156.25−1247.219856
Add similar elements: 13857.9984sin2(θ)+1247.219856sin2(θ)=15105.218256sin2(θ)=−2943sin(θ)+15105.218256sin2(θ)+156.25−1247.219856
Add/Subtract the numbers: 156.25−1247.219856=−1090.969856=15105.218256sin2(θ)−2943sin(θ)−1090.969856
=15105.218256sin2(θ)−2943sin(θ)−1090.969856
=15105.218256sin2(θ)−2943sin(θ)−1090.969856
−1090.969856+15105.218256sin2(θ)−2943sin(θ)=0
Solve by substitution
−1090.969856+15105.218256sin2(θ)−2943sin(θ)=0
Let: sin(θ)=u−1090.969856+15105.218256u2−2943u=0
−1090.969856+15105.218256u2−2943u=0:u=20.19483…+0.32685…​​,u=20.19483…−0.32685…​​
−1090.969856+15105.218256u2−2943u=0
Divide both sides by 15105.218256−15105.2182561090.969856​+15105.21825615105.218256u2​−15105.2182562943u​=15105.2182560​
Write in the standard form ax2+bx+c=0u2−0.19483…u−0.07222…=0
Solve with the quadratic formula
u2−0.19483…u−0.07222…=0
Quadratic Equation Formula:
For a=1,b=−0.19483…,c=−0.07222…u1,2​=2⋅1−(−0.19483…)±(−0.19483…)2−4⋅1⋅(−0.07222…)​​
u1,2​=2⋅1−(−0.19483…)±(−0.19483…)2−4⋅1⋅(−0.07222…)​​
(−0.19483…)2−4⋅1⋅(−0.07222…)​=0.32685…​
(−0.19483…)2−4⋅1⋅(−0.07222…)​
Apply rule −(−a)=a=(−0.19483…)2+4⋅1⋅0.07222…​
Apply exponent rule: (−a)n=an,if n is even(−0.19483…)2=0.19483…2=0.19483…2+4⋅1⋅0.07222…​
Multiply the numbers: 4⋅1⋅0.07222…=0.28889…=0.19483…2+0.28889…​
0.19483…2=0.03796…=0.03796…+0.28889…​
Add the numbers: 0.03796…+0.28889…=0.32685…=0.32685…​
u1,2​=2⋅1−(−0.19483…)±0.32685…​​
Separate the solutionsu1​=2⋅1−(−0.19483…)+0.32685…​​,u2​=2⋅1−(−0.19483…)−0.32685…​​
u=2⋅1−(−0.19483…)+0.32685…​​:20.19483…+0.32685…​​
2⋅1−(−0.19483…)+0.32685…​​
Apply rule −(−a)=a=2⋅10.19483…+0.32685…​​
Multiply the numbers: 2⋅1=2=20.19483…+0.32685…​​
u=2⋅1−(−0.19483…)−0.32685…​​:20.19483…−0.32685…​​
2⋅1−(−0.19483…)−0.32685…​​
Apply rule −(−a)=a=2⋅10.19483…−0.32685…​​
Multiply the numbers: 2⋅1=2=20.19483…−0.32685…​​
The solutions to the quadratic equation are:u=20.19483…+0.32685…​​,u=20.19483…−0.32685…​​
Substitute back u=sin(θ)sin(θ)=20.19483…+0.32685…​​,sin(θ)=20.19483…−0.32685…​​
sin(θ)=20.19483…+0.32685…​​,sin(θ)=20.19483…−0.32685…​​
sin(θ)=20.19483…+0.32685…​​:θ=arcsin(20.19483…+0.32685…​​)+2πn,θ=π−arcsin(20.19483…+0.32685…​​)+2πn
sin(θ)=20.19483…+0.32685…​​
Apply trig inverse properties
sin(θ)=20.19483…+0.32685…​​
General solutions for sin(θ)=20.19483…+0.32685…​​sin(x)=a⇒x=arcsin(a)+2πn,x=π−arcsin(a)+2πnθ=arcsin(20.19483…+0.32685…​​)+2πn,θ=π−arcsin(20.19483…+0.32685…​​)+2πn
θ=arcsin(20.19483…+0.32685…​​)+2πn,θ=π−arcsin(20.19483…+0.32685…​​)+2πn
sin(θ)=20.19483…−0.32685…​​:θ=arcsin(20.19483…−0.32685…​​)+2πn,θ=π+arcsin(−20.19483…−0.32685…​​)+2πn
sin(θ)=20.19483…−0.32685…​​
Apply trig inverse properties
sin(θ)=20.19483…−0.32685…​​
General solutions for sin(θ)=20.19483…−0.32685…​​sin(x)=−a⇒x=arcsin(−a)+2πn,x=π+arcsin(a)+2πnθ=arcsin(20.19483…−0.32685…​​)+2πn,θ=π+arcsin(−20.19483…−0.32685…​​)+2πn
θ=arcsin(20.19483…−0.32685…​​)+2πn,θ=π+arcsin(−20.19483…−0.32685…​​)+2πn
Combine all the solutionsθ=arcsin(20.19483…+0.32685…​​)+2πn,θ=π−arcsin(20.19483…+0.32685…​​)+2πn,θ=arcsin(20.19483…−0.32685…​​)+2πn,θ=π+arcsin(−20.19483…−0.32685…​​)+2πn
Verify solutions by plugging them into the original equation
Check the solutions by plugging them into 117.72sin(θ)−35.316cos(θ)−12.5=0
Remove the ones that don't agree with the equation.
Check the solution arcsin(20.19483…+0.32685…​​)+2πn:True
arcsin(20.19483…+0.32685…​​)+2πn
Plug in n=1arcsin(20.19483…+0.32685…​​)+2π1
For 117.72sin(θ)−35.316cos(θ)−12.5=0plug inθ=arcsin(20.19483…+0.32685…​​)+2π1117.72sin(arcsin(20.19483…+0.32685…​​)+2π1)−35.316cos(arcsin(20.19483…+0.32685…​​)+2π1)−12.5=0
Refine0=0
⇒True
Check the solution π−arcsin(20.19483…+0.32685…​​)+2πn:False
π−arcsin(20.19483…+0.32685…​​)+2πn
Plug in n=1π−arcsin(20.19483…+0.32685…​​)+2π1
For 117.72sin(θ)−35.316cos(θ)−12.5=0plug inθ=π−arcsin(20.19483…+0.32685…​​)+2π1117.72sin(π−arcsin(20.19483…+0.32685…​​)+2π1)−35.316cos(π−arcsin(20.19483…+0.32685…​​)+2π1)−12.5=0
Refine65.23815…=0
⇒False
Check the solution arcsin(20.19483…−0.32685…​​)+2πn:False
arcsin(20.19483…−0.32685…​​)+2πn
Plug in n=1arcsin(20.19483…−0.32685…​​)+2π1
For 117.72sin(θ)−35.316cos(θ)−12.5=0plug inθ=arcsin(20.19483…−0.32685…​​)+2π1117.72sin(arcsin(20.19483…−0.32685…​​)+2π1)−35.316cos(arcsin(20.19483…−0.32685…​​)+2π1)−12.5=0
Refine−69.36659…=0
⇒False
Check the solution π+arcsin(−20.19483…−0.32685…​​)+2πn:True
π+arcsin(−20.19483…−0.32685…​​)+2πn
Plug in n=1π+arcsin(−20.19483…−0.32685…​​)+2π1
For 117.72sin(θ)−35.316cos(θ)−12.5=0plug inθ=π+arcsin(−20.19483…−0.32685…​​)+2π1117.72sin(π+arcsin(−20.19483…−0.32685…​​)+2π1)−35.316cos(π+arcsin(−20.19483…−0.32685…​​)+2π1)−12.5=0
Refine0=0
⇒True
θ=arcsin(20.19483…+0.32685…​​)+2πn,θ=π+arcsin(−20.19483…−0.32685…​​)+2πn
Show solutions in decimal formθ=0.39333…+2πn,θ=π+0.18957…+2πn

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Frequently Asked Questions (FAQ)

  • What is the general solution for 117.72sin(θ)-35.316cos(θ)-12.5=0 ?

    The general solution for 117.72sin(θ)-35.316cos(θ)-12.5=0 is θ=0.39333…+2pin,θ=pi+0.18957…+2pin
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