What is the general solution for solvefor x,y^1=sin(x) ?

The general solution for solvefor x,y^1=sin(x) is x=arcsin(y)+2pin,x=pi+arcsin(-y)+2pin

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solvefor x,y^1=sin(x)

solve for

x, y^{1} = sin (x)

x = arcsin (y) + 2 πn, x = π + arcsin (- y) + 2 πn

Solution steps

y^{1} = sin (x)

Switch sides

sin (x) = y^{1}

Apply rule

a^{1} = a

sin (x) = y

Apply trig inverse properties

sin (x) = y

General solutions for

sin (x) = y

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin (y) + 2 πn, x = π + arcsin (- y) + 2 πn

x = arcsin (y) + 2 πn, x = π + arcsin (- y) + 2 πn

tan (θ) = \frac{15}{6}

- cos (2 x) = cos^{2} (x) - sin^{2} (x)

tan (θ) = \frac{15}{9}

sin (θ) = - 0.7659

4 cos (x) = - 2

What is the general solution for solvefor x,y^1=sin(x) ?
The general solution for solvefor x,y^1=sin(x) is x=arcsin(y)+2pin,x=pi+arcsin(-y)+2pin