What is the general solution for 0=-8sin(x) ?

The general solution for 0=-8sin(x) is x=2pin,x=pi+2pin

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0=-8sin(x)

0 = - 8 sin (x)

x = 2 πn, x = π + 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

0 = - 8 sin (x)

Switch sides

- 8 sin (x) = 0

Divide both sides by

- 8

- 8 sin (x) = 0

Divide both sides by

- 8

\frac{- 8 sin ( x )}{- 8} = \frac{0}{- 8}

Simplify

sin (x) = 0

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

cos^{2} (x) + 2 cos (x) + 1 = 0, (0, 2 π)

3 sin (2 θ) = 2 sin (θ)

sin (x) \cdot cos^{2} (x) = sin (x)

sinh (y) = - 2

2 sin (θ) = - 3 + 4 sin (θ)

What is the general solution for 0=-8sin(x) ?
The general solution for 0=-8sin(x) is x=2pin,x=pi+2pin