What is the general solution for cos(x)=-1/2 ,0<x<2pi ?

The general solution for cos(x)=-1/2 ,0<x<2pi is x=(2pi)/3 ,x=(4pi)/3

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cos(x)=-1/2 ,0<x<2pi

cos (x) = - \frac{1}{2}, 0 < x < 2 π

x = \frac{2 π}{3}, x = \frac{4 π}{3}

Degrees

x = 12 0^{\circ}, x = 24 0^{\circ}

Solution steps

cos (x) = - \frac{1}{2}, 0 < x < 2 π

General solutions for

cos (x) = - \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solutions for the range

0 < x < 2 π

x = \frac{2 π}{3}, x = \frac{4 π}{3}

cot (θ) = cos (θ)

3 sin^{2} (θ) - cos (θ) + 1 = 0

2 - 2 cos^{2} (x) = 0

3 csc^{3} (x) - 4 csc (x) = 0

tan (θ) = \frac{6.06}{- 33.5}

What is the general solution for cos(x)=-1/2 ,0<x<2pi ?
The general solution for cos(x)=-1/2 ,0<x<2pi is x=(2pi)/3 ,x=(4pi)/3