What is the general solution for 5sin(θ)+3=3 ?

The general solution for 5sin(θ)+3=3 is θ=2pin,θ=pi+2pin

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5sin(θ)+3=3

5 sin (θ) + 3 = 3

θ = 2 πn, θ = π + 2 πn

Degrees

θ = 0^{\circ} + 36 0^{\circ} n, θ = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

5 sin (θ) + 3 = 3

Subtract

3

from both sides

5 sin (θ) + 3 - 3 = 3 - 3

Simplify

5 sin (θ) = 0

Divide both sides by

5

5 sin (θ) = 0

Divide both sides by

5

\frac{5 sin ( θ )}{5} = \frac{0}{5}

Simplify

sin (θ) = 0

sin (θ) = 0

General solutions for

sin (θ) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

θ = 0 + 2 πn, θ = π + 2 πn

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 0 + 2 πn

0 + 2 πn = 2 πn

θ = 2 πn

θ = 2 πn, θ = π + 2 πn

sin (3 x) = 0, 0 < x \leq 2

tan (x) = - 0.35

0 = cos (2 t - \frac{π}{3})

sin (0.5 x) = 0

cos (2 x) = 2 - 3 sin (x), \frac{π}{2} \leq x \leq \frac{3 π}{2}

What is the general solution for 5sin(θ)+3=3 ?
The general solution for 5sin(θ)+3=3 is θ=2pin,θ=pi+2pin