What is the general solution for cos(x)=-1,0<x<2pi ?

The general solution for cos(x)=-1,0<x<2pi is x=pi

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cos(x)=-1,0<x<2pi

cos (x) = - 1, 0 < x < 2 π

x = π

Degrees

x = 18 0^{\circ}

Solution steps

cos (x) = - 1, 0 < x < 2 π

General solutions for

cos (x) = - 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = π + 2 πn

x = π + 2 πn

Solutions for the range

0 < x < 2 π

x = π

\frac{1}{1 + cos ( x )} + \frac{1}{1 - cos ( x )} = 32

sin^{2} (x) = 14

sin (2 x) \cdot cos (3 x) = 0

sin^{2} (x) = - 3

cos (θ) = - \frac{2}{7}

What is the general solution for cos(x)=-1,0<x<2pi ?
The general solution for cos(x)=-1,0<x<2pi is x=pi