What is the general solution for 4tan(x)+4=0,0<= x<2pi ?

The general solution for 4tan(x)+4=0,0<= x<2pi is x=(3pi)/4 ,x=(7pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4tan(x)+4=0,0<= x<2pi

4 tan (x) + 4 = 0, 0 \leq x < 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

Degrees

x = 13 5^{\circ}, x = 31 5^{\circ}

Solution steps

4 tan (x) + 4 = 0, 0 \leq x < 2 π

Move

4

to the right side

4 tan (x) + 4 = 0

Subtract

4

from both sides

4 tan (x) + 4 - 4 = 0 - 4

Simplify

4 tan (x) = - 4

4 tan (x) = - 4

Divide both sides by

4

4 tan (x) = - 4

Divide both sides by

4

\frac{4 tan ( x )}{4} = \frac{- 4}{4}

Simplify

tan (x) = - 1

tan (x) = - 1

General solutions for

tan (x) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

Solutions for the range

0 \leq x < 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

cos^{3} (x) = cos (x), 0 \leq x < 2 π

3 - 2 sin^{2} (x) = 2 sin^{2} (\frac{x}{2})

cot (θ) = - \frac{7}{5}, \frac{3 π}{2} < θ < 2 π, tan (θ)

sin (r) = 0.58

sec (α) = \frac{9}{5}

What is the general solution for 4tan(x)+4=0,0<= x<2pi ?
The general solution for 4tan(x)+4=0,0<= x<2pi is x=(3pi)/4 ,x=(7pi)/4