What is the general solution for cos(y)=-1/2 ?

The general solution for cos(y)=-1/2 is y=(2pi)/3+2pin,y=(4pi)/3+2pin

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cos(y)=-1/2

cos (y) = - \frac{1}{2}

y = \frac{2 π}{3} + 2 πn, y = \frac{4 π}{3} + 2 πn

Degrees

y = 12 0^{\circ} + 36 0^{\circ} n, y = 24 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (y) = - \frac{1}{2}

General solutions for

cos (y) = - \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

y = \frac{2 π}{3} + 2 πn, y = \frac{4 π}{3} + 2 πn

y = \frac{2 π}{3} + 2 πn, y = \frac{4 π}{3} + 2 πn

\frac{2}{1 + sin ( x )} = 3 - 2 sin (x)

x, 4 cos^{2} (x) = 5 + 4 sin (x)

t, y = cos (2 t)

cos (3 x) = \frac{1}{5}

cos^{2} (x) - 5 cos (x) + 6 = 0

What is the general solution for cos(y)=-1/2 ?
The general solution for cos(y)=-1/2 is y=(2pi)/3+2pin,y=(4pi)/3+2pin