What is the general solution for sin(x)=((60*sin(155)))/(97.72) ?

The general solution for sin(x)=((60*sin(155)))/(97.72) is x=0.26249…+360n,x=180-0.26249…+360n

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sin(x)=((60*sin(155)))/(97.72)

sin (x) = \frac{( 60 \cdot sin ( 15 5 ^{\circ} ) )}{97.72}

x = 0.26249 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.26249 \dots + 36 0^{\circ} n

Radians

x = 0.26249 \dots + 2 πn, x = π - 0.26249 \dots + 2 πn

Solution steps

sin (x) = \frac{( 60 sin ( 15 5 ^{\circ} ) )}{97.72}

Apply trig inverse properties

sin (x) = \frac{60 sin ( 15 5 ^{\circ} )}{97.72}

General solutions for

sin (x) = \frac{60 sin ( 15 5 ^{\circ} )}{97.72}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

x = arcsin (\frac{60 sin ( 15 5 ^{\circ} )}{97.72}) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (\frac{60 sin ( 15 5 ^{\circ} )}{97.72}) + 36 0^{\circ} n

x = arcsin (\frac{60 sin ( 15 5 ^{\circ} )}{97.72}) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (\frac{60 sin ( 15 5 ^{\circ} )}{97.72}) + 36 0^{\circ} n

Show solutions in decimal form

x = 0.26249 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.26249 \dots + 36 0^{\circ} n

(1 - 2 cos (x)) (1 + sin (x)) = 0

3 cos (2 x) + 7 sin (x) - 5 = 0

cos^{2} (θ) = \frac{1}{3}

x, sin (\frac{x}{5}) = - \frac{3}{2}

sin (B) = \frac{3}{10}

What is the general solution for sin(x)=((60*sin(155)))/(97.72) ?
The general solution for sin(x)=((60*sin(155)))/(97.72) is x=0.26249…+360n,x=180-0.26249…+360n