What is the general solution for cos(A)-1=0 ?

The general solution for cos(A)-1=0 is A=2pin

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cos(A)-1=0

cos (A) - 1 = 0

A = 2 πn

Degrees

A = 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (A) - 1 = 0

Move

1

to the right side

cos (A) - 1 = 0

Add

1

to both sides

cos (A) - 1 + 1 = 0 + 1

Simplify

cos (A) = 1

cos (A) = 1

General solutions for

cos (A) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

A = 0 + 2 πn

A = 0 + 2 πn

Solve

A = 0 + 2 πn : A = 2 πn

A = 0 + 2 πn

0 + 2 πn = 2 πn

A = 2 πn

A = 2 πn

4 sin (x) + 7 = 3

1 - cos (4 x) = sin (2 x)

tan (θ) = \frac{2}{1}

cos (2 x) = sin^{2} (x)

sec^{2} (x) - 3 tan (x) = 5

What is the general solution for cos(A)-1=0 ?
The general solution for cos(A)-1=0 is A=2pin