{
"query": {
"display": "$$3\\cos^{2}\\left(\\frac{x}{2}\\right)=3$$",
"symbolab_question": "EQUATION#3\\cos^{2}(\\frac{x}{2})=3"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "x=4πn,x=2π+4πn",
"degrees": "x=0^{\\circ }+720^{\\circ }n,x=360^{\\circ }+720^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$3\\cos^{2}\\left(\\frac{x}{2}\\right)=3{\\quad:\\quad}x=4πn,\\:x=2π+4πn$$",
"input": "3\\cos^{2}\\left(\\frac{x}{2}\\right)=3",
"steps": [
{
"type": "interim",
"title": "Solve by substitution",
"input": "3\\cos^{2}\\left(\\frac{x}{2}\\right)=3",
"result": "\\cos\\left(\\frac{x}{2}\\right)=1,\\:\\cos\\left(\\frac{x}{2}\\right)=-1",
"steps": [
{
"type": "step",
"primary": "Let: $$\\cos\\left(\\frac{x}{2}\\right)=u$$",
"result": "3u^{2}=3"
},
{
"type": "interim",
"title": "$$3u^{2}=3{\\quad:\\quad}u=1,\\:u=-1$$",
"input": "3u^{2}=3",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$3$$",
"input": "3u^{2}=3",
"result": "u^{2}=1",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$3$$",
"result": "\\frac{3u^{2}}{3}=\\frac{3}{3}"
},
{
"type": "step",
"primary": "Simplify",
"result": "u^{2}=1"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
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}
},
{
"type": "step",
"primary": "For $$x^{2}=f\\left(a\\right)$$ the solutions are $$x=\\sqrt{f\\left(a\\right)},\\:\\:-\\sqrt{f\\left(a\\right)}$$"
},
{
"type": "step",
"result": "u=\\sqrt{1},\\:u=-\\sqrt{1}"
},
{
"type": "interim",
"title": "$$\\sqrt{1}=1$$",
"input": "\\sqrt{1}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$\\sqrt{1}=1$$",
"result": "=1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7KfzlHGGU7KN8vfEO0eL8NN13jtrSFDx+UNsawjlOjV3ZuCguaNudj5qbY1K8A+fScubCnYZOJ5L8/2gsdymw1PSOscTE6qsKVI9GkIdY/eI="
}
},
{
"type": "interim",
"title": "$$-\\sqrt{1}=-1$$",
"input": "-\\sqrt{1}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$\\sqrt{1}=1$$",
"result": "=-1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
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}
},
{
"type": "step",
"result": "u=1,\\:u=-1"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Substitute back $$u=\\cos\\left(\\frac{x}{2}\\right)$$",
"result": "\\cos\\left(\\frac{x}{2}\\right)=1,\\:\\cos\\left(\\frac{x}{2}\\right)=-1"
}
],
"meta": {
"interimType": "Substitution Method 0Eq"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(\\frac{x}{2}\\right)=1{\\quad:\\quad}x=4πn$$",
"input": "\\cos\\left(\\frac{x}{2}\\right)=1",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\cos\\left(\\frac{x}{2}\\right)=1$$",
"result": "\\frac{x}{2}=0+2πn",
"steps": [
{
"type": "step",
"primary": "$$\\cos\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\cos(x)&x&\\cos(x)\\\\\\hline 0&1&π&-1\\\\\\hline \\frac{π}{6}&\\frac{\\sqrt{3}}{2}&\\frac{7π}{6}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{1}{2}&\\frac{4π}{3}&-\\frac{1}{2}\\\\\\hline \\frac{π}{2}&0&\\frac{3π}{2}&0\\\\\\hline \\frac{2π}{3}&-\\frac{1}{2}&\\frac{5π}{3}&\\frac{1}{2}\\\\\\hline \\frac{3π}{4}&-\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&-\\frac{\\sqrt{3}}{2}&\\frac{11π}{6}&\\frac{\\sqrt{3}}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "\\frac{x}{2}=0+2πn"
}
],
"meta": {
"interimType": "Trig General Solutions cos 1Eq"
}
},
{
"type": "interim",
"title": "Solve $$\\frac{x}{2}=0+2πn:{\\quad}x=4πn$$",
"input": "\\frac{x}{2}=0+2πn",
"steps": [
{
"type": "step",
"primary": "$$0+2πn=2πn$$",
"result": "\\frac{x}{2}=2πn"
},
{
"type": "interim",
"title": "Multiply both sides by $$2$$",
"input": "\\frac{x}{2}=2πn",
"result": "x=4πn",
"steps": [
{
"type": "step",
"primary": "Multiply both sides by $$2$$",
"result": "\\frac{2x}{2}=2\\cdot\\:2πn"
},
{
"type": "step",
"primary": "Simplify",
"result": "x=4πn"
}
],
"meta": {
"interimType": "Multiply Both Sides Specific 1Eq",
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],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "step",
"result": "x=4πn"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(\\frac{x}{2}\\right)=-1{\\quad:\\quad}x=2π+4πn$$",
"input": "\\cos\\left(\\frac{x}{2}\\right)=-1",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\cos\\left(\\frac{x}{2}\\right)=-1$$",
"result": "\\frac{x}{2}=π+2πn",
"steps": [
{
"type": "step",
"primary": "$$\\cos\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\cos(x)&x&\\cos(x)\\\\\\hline 0&1&π&-1\\\\\\hline \\frac{π}{6}&\\frac{\\sqrt{3}}{2}&\\frac{7π}{6}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{1}{2}&\\frac{4π}{3}&-\\frac{1}{2}\\\\\\hline \\frac{π}{2}&0&\\frac{3π}{2}&0\\\\\\hline \\frac{2π}{3}&-\\frac{1}{2}&\\frac{5π}{3}&\\frac{1}{2}\\\\\\hline \\frac{3π}{4}&-\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&-\\frac{\\sqrt{3}}{2}&\\frac{11π}{6}&\\frac{\\sqrt{3}}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "\\frac{x}{2}=π+2πn"
}
],
"meta": {
"interimType": "Trig General Solutions cos 1Eq"
}
},
{
"type": "interim",
"title": "Solve $$\\frac{x}{2}=π+2πn:{\\quad}x=2π+4πn$$",
"input": "\\frac{x}{2}=π+2πn",
"steps": [
{
"type": "interim",
"title": "Multiply both sides by $$2$$",
"input": "\\frac{x}{2}=π+2πn",
"result": "x=2π+4πn",
"steps": [
{
"type": "step",
"primary": "Multiply both sides by $$2$$",
"result": "\\frac{2x}{2}=2π+2\\cdot\\:2πn"
},
{
"type": "step",
"primary": "Simplify",
"result": "x=2π+4πn"
}
],
"meta": {
"interimType": "Multiply Both Sides Specific 1Eq",
"gptData": "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"
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}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
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},
{
"type": "step",
"result": "x=2π+4πn"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"primary": "Combine all the solutions",
"result": "x=4πn,\\:x=2π+4πn"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "3\\cos^{2}(\\frac{x}{2})-3"
},
"showViewLarger": true
}
},
"meta": {
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}
}
Solution
Solution
+1
Degrees
Solution steps
Solve by substitution
Let:
Divide both sides by
Divide both sides by
Simplify
For the solutions are
Apply rule
Apply rule
Substitute back
General solutions for
periodicity table with cycle:
Solve
Multiply both sides by
Multiply both sides by
Simplify
General solutions for
periodicity table with cycle:
Solve
Multiply both sides by
Multiply both sides by
Simplify
Combine all the solutions
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is the general solution for 3cos^2(x/2)=3 ?
The general solution for 3cos^2(x/2)=3 is x=4pin,x=2pi+4pin