What is the general solution for 5sin(x)-20=-15 ?

The general solution for 5sin(x)-20=-15 is x= pi/2+2pin

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5sin(x)-20=-15

5 sin (x) - 20 = - 15

x = \frac{π}{2} + 2 πn

Degrees

x = 9 0^{\circ} + 36 0^{\circ} n

Solution steps

5 sin (x) - 20 = - 15

Move

20

to the right side

5 sin (x) - 20 = - 15

Add

20

to both sides

5 sin (x) - 20 + 20 = - 15 + 20

Simplify

5 sin (x) = 5

5 sin (x) = 5

Divide both sides by

5

5 sin (x) = 5

Divide both sides by

5

\frac{5 sin ( x )}{5} = \frac{5}{5}

Simplify

sin (x) = 1

sin (x) = 1

General solutions for

sin (x) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

cos (x) = \frac{11}{14}

2 sin (θ) cos (θ) + 2 sin (θ) = 0

cot (3 8^{\circ}) = tan (2 x)

sin (x \cdot 240) = 0

sin^{2} (x) + 1 = \frac{3}{2}

What is the general solution for 5sin(x)-20=-15 ?
The general solution for 5sin(x)-20=-15 is x= pi/2+2pin