What is the general solution for cos(x)=-(2sqrt(5))/5 ,pi<x<2pi ?

The general solution for cos(x)=-(2sqrt(5))/5 ,pi<x<2pi is x=-2.67794…+2pi

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cos(x)=-(2sqrt(5))/5 ,pi<x<2pi

cos (x) = - \frac{2 5}{5}, π < x < 2 π

x = - 2.67794 \dots + 2 π

Degrees

x = 206.56505 \dots^{\circ}

Solution steps

cos (x) = - \frac{2 5}{5}, π < x < 2 π

Apply trig inverse properties

cos (x) = - \frac{2 5}{5}

General solutions for

cos (x) = - \frac{2 5}{5}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

x = arccos (- \frac{2 5}{5}) + 2 πn, x = - arccos (- \frac{2 5}{5}) + 2 πn

x = arccos (- \frac{2 5}{5}) + 2 πn, x = - arccos (- \frac{2 5}{5}) + 2 πn

Solutions for the range

π < x < 2 π

x = - arccos (- \frac{2 5}{5}) + 2 π

Show solutions in decimal form

x = - 2.67794 \dots + 2 π

0 = 3 sin (θ)

2 cos^{(2)} (x) + 32 sin (x) = 4

3 cos (θ) + 2 sec (θ) + 7 = 0

2 cos^{2} (x) + sin (x) - 1 = 0, (0, 2 π)

4 cos^{2} (x) - 2 cos (x) - 1 = 0

What is the general solution for cos(x)=-(2sqrt(5))/5 ,pi<x<2pi ?
The general solution for cos(x)=-(2sqrt(5))/5 ,pi<x<2pi is x=-2.67794…+2pi