English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor A,sin(B+C/2)=cos(A/2)

Solution

solve for

A, sin (B + \frac{C}{2}) = cos (\frac{A}{2})

A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn, A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

Solution steps

sin (B + \frac{C}{2}) = cos (\frac{A}{2})

Switch sides

cos (\frac{A}{2}) = sin (B + \frac{C}{2})

Apply trig inverse properties

cos (\frac{A}{2}) = sin (B + \frac{C}{2})

General solutions for

cos (\frac{A}{2}) = sin (B + \frac{C}{2})

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

\frac{A}{2} = arccos (sin (B + \frac{C}{2})) + 2 πn, \frac{A}{2} = - arccos (sin (B + \frac{C}{2})) + 2 πn

\frac{A}{2} = arccos (sin (B + \frac{C}{2})) + 2 πn, \frac{A}{2} = - arccos (sin (B + \frac{C}{2})) + 2 πn

Solve

\frac{A}{2} = arccos (sin (B + \frac{C}{2})) + 2 πn : A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn

\frac{A}{2} = arccos (sin (B + \frac{C}{2})) + 2 πn

Multiply both sides by

2

\frac{A}{2} = arccos (sin (B + \frac{C}{2})) + 2 πn

Multiply both sides by

2

\frac{2 A}{2} = 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Simplify

\frac{2 A}{2} = 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Simplify

\frac{2 A}{2} : A

\frac{2 A}{2}

Divide the numbers:

\frac{2}{2} = 1

= A

Simplify

2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn : 2 arccos (sin (B + \frac{C}{2})) + 4 πn

2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Multiply the numbers:

2 \cdot 2 = 4

= 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn

Solve

\frac{A}{2} = - arccos (sin (B + \frac{C}{2})) + 2 πn : A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

\frac{A}{2} = - arccos (sin (B + \frac{C}{2})) + 2 πn

Multiply both sides by

2

\frac{A}{2} = - arccos (sin (B + \frac{C}{2})) + 2 πn

Multiply both sides by

2

\frac{2 A}{2} = - 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Simplify

\frac{2 A}{2} = - 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Simplify

\frac{2 A}{2} : A

\frac{2 A}{2}

Divide the numbers:

\frac{2}{2} = 1

= A

Simplify

- 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn : - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

- 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Multiply the numbers:

2 \cdot 2 = 4

= - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn, A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

33 tan (u) = 3

3 sec (2 x + 3) = 4

t, f = 3 cos (ptt h e t a) - 2

sin (θ - π) = - \frac{1}{2}

7 - 2 sin (5 (x + \frac{π}{8})) = 9