What is the general solution for sin(α)=(sqrt(3))/2 ?

The general solution for sin(α)=(sqrt(3))/2 is α= pi/3+2pin,α=(2pi)/3+2pin

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sin(α)=(sqrt(3))/2

sin (α) = \frac{3}{2}

α = \frac{π}{3} + 2 πn, α = \frac{2 π}{3} + 2 πn

Degrees

α = 6 0^{\circ} + 36 0^{\circ} n, α = 12 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (α) = \frac{3}{2}

General solutions for

sin (α) = \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

α = \frac{π}{3} + 2 πn, α = \frac{2 π}{3} + 2 πn

α = \frac{π}{3} + 2 πn, α = \frac{2 π}{3} + 2 πn

x, sin (\frac{x}{x}) = 1

4 sin (θ) + 4 = 0

sin^{2} (a) + 2 cos (a) = \frac{49}{25}

cot (x) + csc (x) = 1

- 3 tan^{2} (x) + 1 = 0

What is the general solution for sin(α)=(sqrt(3))/2 ?
The general solution for sin(α)=(sqrt(3))/2 is α= pi/3+2pin,α=(2pi)/3+2pin