{
"query": {
"display": "$$\\sin\\left(θ\\right)-\\sqrt{3}\\cos\\left(θ\\right)=2$$",
"symbolab_question": "EQUATION#\\sin(θ)-\\sqrt{3}\\cos(θ)=2"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "θ=\\frac{5π}{6}+2πn",
"degrees": "θ=150^{\\circ }+360^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\sin\\left(θ\\right)-\\sqrt{3}\\cos\\left(θ\\right)=2{\\quad:\\quad}θ=\\frac{5π}{6}+2πn$$",
"input": "\\sin\\left(θ\\right)-\\sqrt{3}\\cos\\left(θ\\right)=2",
"steps": [
{
"type": "step",
"primary": "Add $$\\sqrt{3}\\cos\\left(θ\\right)$$ to both sides",
"result": "\\sin\\left(θ\\right)=2+\\sqrt{3}\\cos\\left(θ\\right)"
},
{
"type": "step",
"primary": "Square both sides",
"result": "\\sin^{2}\\left(θ\\right)=\\left(2+\\sqrt{3}\\cos\\left(θ\\right)\\right)^{2}"
},
{
"type": "step",
"primary": "Subtract $$\\left(2+\\sqrt{3}\\cos\\left(θ\\right)\\right)^{2}$$ from both sides",
"result": "\\sin^{2}\\left(θ\\right)-4-4\\sqrt{3}\\cos\\left(θ\\right)-3\\cos^{2}\\left(θ\\right)=0"
},
{
"type": "interim",
"title": "Rewrite using trig identities",
"input": "-4+\\sin^{2}\\left(θ\\right)-3\\cos^{2}\\left(θ\\right)-4\\cos\\left(θ\\right)\\sqrt{3}",
"result": "-3-4\\cos^{2}\\left(θ\\right)-4\\cos\\left(θ\\right)\\sqrt{3}=0",
"steps": [
{
"type": "step",
"primary": "Use the Pythagorean identity: $$\\cos^{2}\\left(x\\right)+\\sin^{2}\\left(x\\right)=1$$",
"secondary": [
"$$\\sin^{2}\\left(x\\right)=1-\\cos^{2}\\left(x\\right)$$"
],
"result": "=-4+1-\\cos^{2}\\left(θ\\right)-3\\cos^{2}\\left(θ\\right)-4\\cos\\left(θ\\right)\\sqrt{3}"
},
{
"type": "interim",
"title": "Simplify $$-4+1-\\cos^{2}\\left(θ\\right)-3\\cos^{2}\\left(θ\\right)-4\\cos\\left(θ\\right)\\sqrt{3}:{\\quad}-4\\cos^{2}\\left(θ\\right)-4\\sqrt{3}\\cos\\left(θ\\right)-3$$",
"input": "-4+1-\\cos^{2}\\left(θ\\right)-3\\cos^{2}\\left(θ\\right)-4\\cos\\left(θ\\right)\\sqrt{3}",
"result": "=-4\\cos^{2}\\left(θ\\right)-4\\sqrt{3}\\cos\\left(θ\\right)-3",
"steps": [
{
"type": "step",
"primary": "Add similar elements: $$-\\cos^{2}\\left(θ\\right)-3\\cos^{2}\\left(θ\\right)=-4\\cos^{2}\\left(θ\\right)$$",
"result": "=-4+1-4\\cos^{2}\\left(θ\\right)-4\\sqrt{3}\\cos\\left(θ\\right)"
},
{
"type": "step",
"primary": "Add/Subtract the numbers: $$-4+1=-3$$",
"result": "=-4\\cos^{2}\\left(θ\\right)-4\\sqrt{3}\\cos\\left(θ\\right)-3"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7T06shGQOeEftvEmzESFae/pWKbkIIJtzjRon000y7xnd+G7JIwOwCJjkBU9qPWCXUpePku2bIkpxpx/sZ1eiUQlAlm5MBjmOz6iqN1PySyXSNOYTjJcTVwfGeGti+Q55n/ziqMrJOwT0L9FRSjIX/O57Suk6r5rx0JR94nMrHwTWwPs1+Gw97t4MeuaNjSYTVeH60jNPIHBoeIeWKi52fhEH2XvHLdCvDXp2zn8AhXQsWPBujxfT+mPs+i/Q1yvZ8QCgvGuvlEPSq2MhjtjxoompXFf3SOUx+H18qfp3MLg="
}
}
],
"meta": {
"interimType": "Trig Rewrite Using Trig identities 0Eq",
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}
},
{
"type": "interim",
"title": "Solve by substitution",
"input": "-3-4\\cos^{2}\\left(θ\\right)-4\\cos\\left(θ\\right)\\sqrt{3}=0",
"result": "\\cos\\left(θ\\right)=-\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "step",
"primary": "Let: $$\\cos\\left(θ\\right)=u$$",
"result": "-3-4u^{2}-4u\\sqrt{3}=0"
},
{
"type": "interim",
"title": "$$-3-4u^{2}-4u\\sqrt{3}=0{\\quad:\\quad}u=-\\frac{\\sqrt{3}}{2}$$",
"input": "-3-4u^{2}-4u\\sqrt{3}=0",
"steps": [
{
"type": "step",
"primary": "Write in the standard form $$ax^{2}+bx+c=0$$",
"result": "-4u^{2}-4\\sqrt{3}u-3=0"
},
{
"type": "interim",
"title": "Solve with the quadratic formula",
"input": "-4u^{2}-4\\sqrt{3}u-3=0",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-4\\sqrt{3}\\right)\\pm\\:\\sqrt{\\left(-4\\sqrt{3}\\right)^{2}-4\\left(-4\\right)\\left(-3\\right)}}{2\\left(-4\\right)}",
"steps": [
{
"type": "definition",
"title": "Quadratic Equation Formula:",
"text": "For a quadratic equation of the form $$ax^2+bx+c=0$$ the solutions are <br/>$${\\quad}x_{1,\\:2}=\\frac{-b\\pm\\sqrt{b^2-4ac}}{2a}$$"
},
{
"type": "step",
"primary": "For $${\\quad}a=-4,\\:b=-4\\sqrt{3},\\:c=-3$$",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-4\\sqrt{3}\\right)\\pm\\:\\sqrt{\\left(-4\\sqrt{3}\\right)^{2}-4\\left(-4\\right)\\left(-3\\right)}}{2\\left(-4\\right)}"
}
],
"meta": {
"interimType": "Solving The Quadratic Equation With Quadratic Formula Definition 0Eq",
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}
},
{
"type": "interim",
"title": "$$\\left(-4\\sqrt{3}\\right)^{2}-4\\left(-4\\right)\\left(-3\\right)=0$$",
"input": "\\left(-4\\sqrt{3}\\right)^{2}-4\\left(-4\\right)\\left(-3\\right)",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-4\\sqrt{3}\\right)\\pm\\:\\sqrt{0}}{2\\left(-4\\right)}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$-\\left(-a\\right)=a$$",
"result": "=\\left(-4\\sqrt{3}\\right)^{2}-4\\cdot\\:4\\cdot\\:3"
},
{
"type": "interim",
"title": "$$\\left(-4\\sqrt{3}\\right)^{2}=4^{2}\\cdot\\:3$$",
"input": "\\left(-4\\sqrt{3}\\right)^{2}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(-a\\right)^{n}=a^{n},\\:$$if $$n$$ is even",
"secondary": [
"$$\\left(-4\\sqrt{3}\\right)^{2}=\\left(4\\sqrt{3}\\right)^{2}$$"
],
"result": "=\\left(4\\sqrt{3}\\right)^{2}"
},
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(a\\cdot\\:b\\right)^{n}=a^{n}b^{n}$$",
"result": "=4^{2}\\left(\\sqrt{3}\\right)^{2}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "interim",
"title": "$$\\left(\\sqrt{3}\\right)^{2}:{\\quad}3$$",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt{a}=a^{\\frac{1}{2}}$$",
"result": "=\\left(3^{\\frac{1}{2}}\\right)^{2}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(a^{b}\\right)^{c}=a^{bc}$$",
"result": "=3^{\\frac{1}{2}\\cdot\\:2}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "interim",
"title": "$$\\frac{1}{2}\\cdot\\:2=1$$",
"input": "\\frac{1}{2}\\cdot\\:2",
"result": "=3",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:2}{2}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$2$$",
"result": "=1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l3vTdf410Ywhq1vZ0kzF8e30Fwl9QKPJxyO/TFRCb5Grju+5Z51e/ZZSD3gRHwjBE9/03SOiEv+BIHutWLr6nUfz18ijmoplMAomfJM9x8W1GdKgiNs+PolKvTuWzYk/"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"result": "=4^{2}\\cdot\\:3"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s71xvHyH5eNNgs8yW3fa2CKydVBn2NNCFZqg4ZoVh6UwqjkVi15I8rBefLi4Iyt2wr4/14o8RLtSK0WJRLt3AWMbu7qyZDwFK9jWGpMmc0pr4LfOxeCwWHeBw2KfnPes1vMdGh0b4sYpbe5HFlR6NPJA=="
}
},
{
"type": "interim",
"title": "$$4\\cdot\\:4\\cdot\\:3=48$$",
"input": "4\\cdot\\:4\\cdot\\:3",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$4\\cdot\\:4\\cdot\\:3=48$$",
"result": "=48"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7aqTaUg1qT9nDhx1eUoutzxUbjr1up91GPxQqAij33CujkVi15I8rBefLi4Iyt2wrCklV65q5uyJBBcrfcaVZq7xcSXgbJgwa5HuBBkPlckn++yrn+9cNysRon8HIu7bT"
}
},
{
"type": "step",
"result": "=4^{2}\\cdot\\:3-48"
},
{
"type": "interim",
"title": "$$4^{2}\\cdot\\:3=48$$",
"input": "4^{2}\\cdot\\:3",
"steps": [
{
"type": "step",
"primary": "$$4^{2}=16$$",
"result": "=16\\cdot\\:3"
},
{
"type": "step",
"primary": "Multiply the numbers: $$16\\cdot\\:3=48$$",
"result": "=48"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7VPQv5NmETWojg73v8B9EnC061ljBSPJeENOw2efoSWumgEsDh9eg4me0entNzllgwUz9JjPZK5WSZB53PR+nvQW+99ohgnhk2vrkHIRsmBUkt3WiGR7ZaCaXvz77bMjS"
}
},
{
"type": "step",
"result": "=48-48"
},
{
"type": "step",
"primary": "Subtract the numbers: $$48-48=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s71xvHyH5eNNgs8yW3fa2CK565HV5Etvy5npqB8iJxZzHehkKrn0era9rz8TlL+x/vZuJKdCFsPJy1+5gBMEc9dkt+ykOJBuJSRvF8I9Rrs53zTI/i1xF2GOqdQtBTT+c8wT7KbPrmvDecvDbmS27gbQ=="
}
},
{
"type": "step",
"result": "u=\\frac{-\\left(-4\\sqrt{3}\\right)}{2\\left(-4\\right)}"
},
{
"type": "interim",
"title": "$$\\frac{-\\left(-4\\sqrt{3}\\right)}{2\\left(-4\\right)}=-\\frac{\\sqrt{3}}{2}$$",
"input": "\\frac{-\\left(-4\\sqrt{3}\\right)}{2\\left(-4\\right)}",
"result": "u=-\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "step",
"primary": "Remove parentheses: $$\\left(-a\\right)=-a,\\:-\\left(-a\\right)=a$$",
"result": "=\\frac{4\\sqrt{3}}{-2\\cdot\\:4}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:4=8$$",
"result": "=\\frac{4\\sqrt{3}}{-8}"
},
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{a}{-b}=-\\frac{a}{b}$$",
"result": "=-\\frac{4\\sqrt{3}}{8}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$4$$",
"result": "=-\\frac{\\sqrt{3}}{2}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7BaRGlw68yflRXEFZzbCaTGInUDCP7b00dXLyj7VdDNctOtZYwUjyXhDTsNnn6ElryOsg4xTbsj8PJfnagYu7Qycg0t9KufQ5/Ecxx5MB743/P/+v51eTuH2/F4MIu5mqVkJ7mOgTTTE7+LV6kzrc+jdepsiTxBpWU6vmWa+XxBom/e8+HIkQc4F7XJ2JfHIpbqwnNL+vkns16SbvknXX+A=="
}
},
{
"type": "step",
"primary": "The solution to the quadratic equation is:",
"result": "u=-\\frac{\\sqrt{3}}{2}"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Substitute back $$u=\\cos\\left(θ\\right)$$",
"result": "\\cos\\left(θ\\right)=-\\frac{\\sqrt{3}}{2}"
}
],
"meta": {
"interimType": "Substitution Method 0Eq"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(θ\\right)=-\\frac{\\sqrt{3}}{2}{\\quad:\\quad}θ=\\frac{5π}{6}+2πn,\\:θ=\\frac{7π}{6}+2πn$$",
"input": "\\cos\\left(θ\\right)=-\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\cos\\left(θ\\right)=-\\frac{\\sqrt{3}}{2}$$",
"result": "θ=\\frac{5π}{6}+2πn,\\:θ=\\frac{7π}{6}+2πn",
"steps": [
{
"type": "step",
"primary": "$$\\cos\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\cos(x)&x&\\cos(x)\\\\\\hline 0&1&π&-1\\\\\\hline \\frac{π}{6}&\\frac{\\sqrt{3}}{2}&\\frac{7π}{6}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{1}{2}&\\frac{4π}{3}&-\\frac{1}{2}\\\\\\hline \\frac{π}{2}&0&\\frac{3π}{2}&0\\\\\\hline \\frac{2π}{3}&-\\frac{1}{2}&\\frac{5π}{3}&\\frac{1}{2}\\\\\\hline \\frac{3π}{4}&-\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&-\\frac{\\sqrt{3}}{2}&\\frac{11π}{6}&\\frac{\\sqrt{3}}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "θ=\\frac{5π}{6}+2πn,\\:θ=\\frac{7π}{6}+2πn"
}
],
"meta": {
"interimType": "Trig General Solutions cos 1Eq"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"primary": "Combine all the solutions",
"result": "θ=\\frac{5π}{6}+2πn,\\:θ=\\frac{7π}{6}+2πn"
},
{
"type": "interim",
"title": "Verify solutions by plugging them into the original equation",
"steps": [
{
"type": "step",
"primary": "Check the solutions by plugging them into $$\\sin\\left(θ\\right)-\\sqrt{3}\\cos\\left(θ\\right)=2$$<br/>Remove the ones that don't agree with the equation."
},
{
"type": "interim",
"title": "Check the solution $$\\frac{5π}{6}+2πn:{\\quad}$$True",
"input": "\\frac{5π}{6}+2πn",
"steps": [
{
"type": "step",
"primary": "Plug in $$n=1$$",
"result": "\\frac{5π}{6}+2π1"
},
{
"type": "step",
"primary": "For $$\\sin\\left(θ\\right)-\\sqrt{3}\\cos\\left(θ\\right)=2{\\quad}$$plug in$${\\quad}θ=\\frac{5π}{6}+2π1$$",
"result": "\\sin\\left(\\frac{5π}{6}+2π1\\right)-\\sqrt{3}\\cos\\left(\\frac{5π}{6}+2π1\\right)=2"
},
{
"type": "step",
"primary": "Refine",
"result": "2=2"
},
{
"type": "step",
"result": "\\Rightarrow\\:\\mathrm{True}"
}
],
"meta": {
"interimType": "Check One Solution 1Eq"
}
},
{
"type": "interim",
"title": "Check the solution $$\\frac{7π}{6}+2πn:{\\quad}$$False",
"input": "\\frac{7π}{6}+2πn",
"steps": [
{
"type": "step",
"primary": "Plug in $$n=1$$",
"result": "\\frac{7π}{6}+2π1"
},
{
"type": "step",
"primary": "For $$\\sin\\left(θ\\right)-\\sqrt{3}\\cos\\left(θ\\right)=2{\\quad}$$plug in$${\\quad}θ=\\frac{7π}{6}+2π1$$",
"result": "\\sin\\left(\\frac{7π}{6}+2π1\\right)-\\sqrt{3}\\cos\\left(\\frac{7π}{6}+2π1\\right)=2"
},
{
"type": "step",
"primary": "Refine",
"result": "1=2"
},
{
"type": "step",
"result": "\\Rightarrow\\:\\mathrm{False}"
}
],
"meta": {
"interimType": "Check One Solution 1Eq"
}
}
],
"meta": {
"interimType": "Check Solutions Plug Preface 1Eq"
}
},
{
"type": "step",
"result": "θ=\\frac{5π}{6}+2πn"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "θ",
"plotRequest": "\\sin(θ)-\\sqrt{3}\\cos(θ)-2"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
Add to both sides
Square both sides
Subtract from both sides
Rewrite using trig identities
Use the Pythagorean identity:
Simplify
Add similar elements:
Add/Subtract the numbers:
Solve by substitution
Let:
Write in the standard form
Solve with the quadratic formula
Quadratic Equation Formula:
For
Apply rule
Apply exponent rule: if is even
Apply exponent rule:
Apply radical rule:
Apply exponent rule:
Multiply fractions:
Cancel the common factor:
Multiply the numbers:
Multiply the numbers:
Subtract the numbers:
Remove parentheses:
Multiply the numbers:
Apply the fraction rule:
Cancel the common factor:
The solution to the quadratic equation is:
Substitute back
General solutions for
periodicity table with cycle:
Combine all the solutions
Verify solutions by plugging them into the original equation
Check the solutions by plugging them into
Remove the ones that don't agree with the equation.
Check the solution True
Plug in
For plug in
Refine
Check the solution False
Plug in
For plug in
Refine
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is the general solution for sin(θ)-sqrt(3)cos(θ)=2 ?
The general solution for sin(θ)-sqrt(3)cos(θ)=2 is θ=(5pi)/6+2pin